我正在使用vanilla javascript制作一个简单的刽子手游戏,并且希望在玩家失败后重置游戏。具体来说,我想: 1.重置“guessRemain”变量 2.清除“猜测”ID,因此没有显示猜测的字母 3.从数组中选择另一个随机单词。
提前感谢您的帮助!
<!DOCTYPE html>
<html lang="en-us">
<head>
<meta charset="UTF-8">
<title>Hangman Game</title>
<link rel="stylesheet" type="text/css" href="assets\css\reset.css"/>
<link rel="stylesheet" type="text/css" href="assets\css\style.css">
<link href="https://fonts.googleapis.com/css?family=Lato" rel="stylesheet">
<script src="https://use.fontawesome.com/ca6de464ee.js"></script>
</head>
<body>
<div id="white">
<img src="assets\images\turkey.png" alt="turkey" class="turkeyImage">
</div>
<div id="orangebox">
<h4>thanksgiving</h4>
<h4 class="hangman">hangman</h4>
</div>
<div class="instructions">
<h1>Instructions:</h1>
<br/>
<h2>1. Guess a Thanksgiving dish!</h2>
<br/>
<h3>2. Press any key to begin.</h3>
</div>
<div class="display">
<p class="greywords">Current Word:</p>
<br/>
<p id="current"></p>
<br/>
<br/>
<p class ="greywords">Number of Guesses Remaining:</p>
<br/>
<p id="remain"></p>
<br>
<br/>
<p class="greywords">Letters Already Guessed:</p>
<p id="guess"></p>
<br>
<br/>
<p class="greywords">Wins:</p>
<p id="win"></p>
<br>
<br/>
<p class="greywords">Losses:</p>
<p id="loss"></p>
</div>
<!-- End of HTML -->
<script type="text/javascript">
// Step 2: create variable of the food words
var wins = 1;
var losses = 1;
var guessRemain = 10;
var foodWords = [
"pie",
"turkey",
"bacon",
"bread"
];
// Step 1: display remaining gueses
document.getElementById("remain").innerHTML = guessRemain;
// Step 3: create a variable to pick a random word from that array
var randomWord = foodWords[Math.floor(Math.random() * foodWords.length)];
console.log(randomWord);
//Step 4: make it count the number of letters in that word that you just picked
var count = [];
for (var i = 0; i < randomWord.length; i++) {
count[i] = "_ ";
}
//Step 5: write the var on the screen
document.getElementById("current").innerHTML = count;
//Step 6: have it recognize that there are remaining letters
var remainingLetters = randomWord.length;
console.log("I HAVE " + remainingLetters + " left");
//Step 7: function for when they click a key
document.onkeyup=function(event) {
var userGuess = event.key;
document.getElementById("guess").innerHTML += userGuess + " ";
// console.log(randomWord.length);
if (randomWord.includes(userGuess)) {
// console.log("test");
// Step 7: if this statment is true, then modify the count variable, replace the dash in count with letter, and it has the correct position, and display the letter
var guessIndex = randomWord.indexOf(userGuess);
//console.log(randomWord.indexOf(userGuess));
count[guessIndex] = userGuess
//console.log(count);
document.getElementById("current").innerHTML = count;
remainingLetters--;
console.log("I HAVE " + remainingLetters + " left");
if (remainingLetters === 0) {
document.getElementById("win").innerHTML = wins++;
console.log("I have won");}
}
// Step 8: if not true, then subtract a guess
else {
document.getElementById("remain").innerHTML = guessRemain--;
document.getElementById("remain").innerHTML = guessRemain;
if (guessRemain === 0) {
document.getElementById("loss").innerHTML = losses++;
console.log("I have lost");
}
}
}
// Step 10: if there are no letters remaining in count, then add "1" to the win id and reset the page
// if (remainingLetters === 0) {
// document.getElementById("#win").innerHTML = winSs++;
// console.log("I have won");
//console.log("i win");
// function reset() {
// document.getElementById("display").reset();
// }
// }
// Step 11: if there are no guesses remaining, add a "1" to the loss id and reset the page
// if (remainingGuess < 0) {
// document.getElementById("#loss").innerHTML = ++1;
// function reset() {
// document.getElementById("display").reset();
// }
// }
</script>
</body>
<div class="footer">
</div>
</html>
答案 0 :(得分:0)
只需设置变量,即可重置&#34; guessRemain
您只需输入
guessRemain = 10;
在你的重置函数中,对于任何其他变量也是如此。
至于网页上已经显示的猜测,你可以做类似的事情
document.getElementById("guess").innerHTML = "";
希望有所帮助:)
答案 1 :(得分:0)
首先,通过将guess
设置为空字符串,清除步骤1-6中某处的innerHTML
元素。按照步骤1-6将它们放在一个名为initialize
的函数中,如下所示:
修改:声明您的变量wins
,losses
,guessRemain
,foodWords
,randomWords
,count
,remainingLetters
位于以下函数之外,以便您可以在onkeyup
处理程序中访问它们
var wins, losses, guessRemain, foodWords, randomWords, count, remainingLetters;
function initialize() {
// Step 1: create variable of the food words
wins = 1;
losses = 1;
guessRemain = 10;
foodWords = [
"pie",
"turkey",
"bacon",
"bread"
];
// Clear the guess
document.getElementById("guess").innerHTML = "";
// Step 2: display remaining gueses
document.getElementById("remain").innerHTML = guessRemain;
// Step 3: create a variable to pick a random word from that array
randomWord = foodWords[Math.floor(Math.random() * foodWords.length)];
console.log(randomWord);
//Step 4: make it count the number of letters in that word that you just picked
count = [];
for (var i = 0; i < randomWord.length; i++) {
count[i] = "_ ";
}
//Step 5: write the var on the screen
document.getElementById("current").innerHTML = count;
//Step 6: have it recognize that there are remaining letters
remainingLetters = randomWord.length;
console.log("I HAVE " + remainingLetters + " left");
}
在代码中的某个位置(initialize()
处理程序之外)调用函数onkeyup
,以便首次初始化游戏。
现在,只要您想重置游戏,就可以重复使用initialize
功能。例如,你可以在游戏结束时执行类似的操作(将此代码放在onkeyup
处理程序的底部):
if (remainingLetters === 0 || remainingGuess === 0) {
inititalize();
}