在我的代码中,我必须运行一个大量使用递归和并行流处理的任务,以便深入了解可能的游戏移动树并决定什么是最佳移动。这需要花费很多时间,因此为了防止用户等待太长时间以使计算机“思考”我想要设置超出1000毫秒的时间。如果在1000毫秒内找不到最佳移动,则计算机将随机移动。 我的问题是虽然我在Future上调用cancel(可能中断设置为true),但任务不会中断,繁忙的线程会在后台继续运行。 我试图定期检查当前的isInterrupted()然后尝试纾困,但这没有帮助。 有什么想法吗?
以下是我的代码:
public Move bestMove() {
ExecutorService executor = Executors.newSingleThreadExecutor();
Callable<Move> callable = () -> bestEntry(bestMoves()).getKey();
Future<Move> future = executor.submit(callable);
try {
return future.get(1000, TimeUnit.MILLISECONDS);
} catch (InterruptedException e) {
System.exit(0);
} catch (ExecutionException e) {
throw new RuntimeException(e);
} catch (TimeoutException e) {
future.cancel(true);
return randomMove();
}
return null;
}
private Move randomMove() {
Random random = new Random();
List<Move> moves = state.possibleMoves();
return moves.get(random.nextInt(moves.size()));
}
private <K> Map.Entry<K, Double> bestEntry(Map<K, Double> map) {
List<Map.Entry<K, Double>> list = new ArrayList<>(map.entrySet());
Collections.sort(list, (e1, e2) -> (int) (e2.getValue() - e1.getValue()));
return list.get(0);
}
private <K> Map.Entry<K, Double> worstEntry(Map<K, Double> map) {
List<Map.Entry<K, Double>> list = new ArrayList<>(map.entrySet());
Collections.sort(list, (e1, e2) -> (int) (e1.getValue() - e2.getValue()));
return list.get(0);
}
private Map<Move, Double> bestMoves() {
Map<Move, Double> moves = new HashMap<>();
state.possibleMoves().stream().parallel().forEach(move -> {
if (!Thread.currentThread().isInterrupted()) {
Game newState = state.playMove(move);
Double score = newState.isTerminal() ? newState.utility()
: worstEntry(new (newState).worstMoves()).getValue();
moves.put(move, score);
}
});
return moves;
}
private Map<Move, Double> worstMoves() {
Map<Move, Double> moves = new HashMap<>();
state.possibleMoves().stream().parallel().forEach(move -> {
if (!Thread.currentThread().isInterrupted()) {
Game newState = state.playMove(move);
Double score = newState.isTerminal() ? -newState.utility()
: bestEntry(new (newState).bestMoves()).getValue();
moves.put(move, score);
}
});
return moves;
}
ps:我也试过没有“parallel()”但是仍然有一个线程在运行。
提前致谢。
答案 0 :(得分:0)
Future.cancel
只需将主题设置为interrupted
,然后您的代码必须将其视为以下内容:
public static void main(String[] args) throws InterruptedException {
final ExecutorService executor = Executors.newSingleThreadExecutor();
final Future<Integer> future = executor.submit(() -> count());
try {
System.out.println(future.get(1, TimeUnit.SECONDS));
} catch (Exception e){
future.cancel(true);
e.printStackTrace();
}finally {
System.out.printf("status=finally, cancelled=%s, done=%s%n", future.isCancelled(), future.isDone());
executor.shutdown();
}
}
static int count() throws InterruptedException {
while (!Thread.interrupted());
throw new InterruptedException();
}
正如你可以看到count
继续检查线程是否可以继续运行,你必须明白,实际上并不能保证如果她不想要运行Thread就可以停止
参考:
更新 2017-11-18 23:22
我编写了一个FutureTask扩展,即使代码不尊重interrupt
信号,也能够尝试停止线程。请记住,它是不安全的,因为Thread.stop
方法is deprecated,无论如何它正在工作,如果你真的需要它可以使用它(请阅读之前的Thread.stop弃用说明,例如,如果你正在使用锁,然后运行.stop会导致死锁。)
测试代码
public static void main(String[] args) throws InterruptedException {
final ExecutorService executor = newFixedSizeExecutor(1);
final Future<Integer> future = executor.submit(() -> count());
try {
System.out.println(future.get(1, TimeUnit.SECONDS));
} catch (Exception e){
future.cancel(true);
e.printStackTrace();
}
System.out.printf("status=finally, cancelled=%s, done=%s%n", future.isCancelled(), future.isDone());
executor.shutdown();
}
static int count() throws InterruptedException {
while (true);
}
自定义执行器
static ThreadPoolExecutor newFixedSizeExecutor(final int threads) {
return new ThreadPoolExecutor(threads, threads, 0L, TimeUnit.MILLISECONDS, new LinkedBlockingQueue<>()){
protected <T> RunnableFuture<T> newTaskFor(Callable<T> callable) {
return new StoppableFutureTask<>(new FutureTask<>(callable));
}
};
}
static class StoppableFutureTask<T> implements RunnableFuture<T> {
private final FutureTask<T> future;
private Field runnerField;
public StoppableFutureTask(FutureTask<T> future) {
this.future = future;
try {
final Class clazz = future.getClass();
runnerField = clazz.getDeclaredField("runner");
runnerField.setAccessible(true);
} catch (Exception e) {
throw new Error(e);
}
}
@Override
public boolean cancel(boolean mayInterruptIfRunning) {
final boolean cancelled = future.cancel(mayInterruptIfRunning);
if(cancelled){
try {
((Thread) runnerField.get(future)).stop();
} catch (Exception e) {
throw new Error(e);
}
}
return cancelled;
}
@Override
public boolean isCancelled() {
return future.isCancelled();
}
@Override
public boolean isDone() {
return future.isDone();
}
@Override
public T get() throws InterruptedException, ExecutionException {
return future.get();
}
@Override
public T get(long timeout, TimeUnit unit) throws InterruptedException, ExecutionException, TimeoutException {
return future.get(timeout, unit);
}
@Override
public void run() {
future.run();
}
}
输出
java.util.concurrent.TimeoutException
at java.util.concurrent.FutureTask.get(FutureTask.java:205)
at com.mageddo.spark.sparkstream_1.Main$StoppableFutureTask.get(Main.java:91)
at com.mageddo.spark.sparkstream_1.Main.main(Main.java:20)
status=finally, cancelled=true, done=true
Process finished with exit code 0
答案 1 :(得分:0)
谢谢大家的回答。我想我找到了一个更简单的解决方案。 首先,我认为future.cancel(true)不起作用的原因是因为它可能只在启动任务的线程上设置了中断标志。 (即与未来相关联的线程)。 但是因为任务本身使用并行流处理,它会在不会被中断的线程上生成工作者,因此我无法定期检查isInterrupted()标志。 &#34;解决方案&#34; (或者更多的解决方法)我发现在我的算法对象中保留我自己的中断标志,并在取消任务时手动将其设置为true。因为所有线程都在同一个实例上工作,所以它们都可以访问被中断的标志并且它们服从。