Question

$query = Doctrine_Query::create()
->select('IF(m.sender_id = ?, m.receiver_id, m.sender_id) AS uid', $my_id)
->from('Message m')
->where('m.receiver_id = ? OR m.sender_id = ?', array($my_id,$my_id))
->groupBy('uid')

我无法按'uid'分组，好像AS uid根本不工作......

如果我尝试通过 - ＆gt; getSqlQuery（）检索生成的sql并直接在Mysql中试用它，它就可以工作。

SELECT IF(s.sender_id = 1, s.receiver_id, s.sender_id) AS s__0 
FROM message s 
WHERE (s.receiver_id = 1 OR s.sender_id = 1) GROUP BY s__0

Answer 1

proc sql;
  create view have_sorted_by_month_year as
  select 
    put(date,monname3.) as month_name,
    year(date) as year,
    percent 
  from have
  order by month(date), year(date);
quit;

proc transpose data=have_sorted_by_month_year out=want(drop=_name_);
  by month_name notsorted;
  var percent;
  id year;
run;

proc print data=want;
run;

----------------------------------

       month_
Obs     name        _2015       _2016       _2017       _2018       _2019

  1     Jan      0.201501    0.201601    0.201701    0.201801    0.201901
  2     Feb      0.201502    0.201602    0.201702    0.201802    0.201902
  3     Mar      0.201503    0.201603    0.201703    0.201803    0.201903
  4     Apr      0.201504    0.201604    0.201704    0.201804    0.201904
  5     May      0.201505    0.201605    0.201705    0.201805    0.201905
  6     Jun      0.201506    0.201606    0.201706    0.201806    0.201906
  7     Jul      0.201507    0.201607    0.201707    0.201807    0.201907
  8     Aug      0.201508    0.201608    0.201708    0.201808    0.201908
  9     Sep      0.201509    0.201609    0.201709    0.201809    0.201909
 10     Oct      0.201510    0.201610    0.201710    0.201810    0.201910
 11     Nov      0.201511    0.201611    0.201711    0.201811    0.201911
 12     Dec      0.201512    0.201612    0.201712    0.201812    0.201912

如何在doctrine和SELECT AS中正确使用IF语句？

1 个答案: