//my code is on java code on employ details using console
//my input is no.of employess
//i am taking input a employ details
//function on searching for a given employ for a given id
//代码含义 // #String employee [] [] = new String [numberOfEmployees] [12];将存储//使用细节 // #String输入将采用字符串格式的员工详细信息。
import java.util.Scanner;
public class EmployeeManagement {
public static void main(String args[]){
Scanner read=new Scanner(System.in);
System.out.println("Enter the no.of employees");
int numberOfEmployees=read.nextInt();//GIVEN INPUT FOR NO.OF EMPLOYESS
int employeeId;
String employee[][]=new String[numberOfEmployees][12];
for(int inner=0;inner<numberOfEmployees;inner++){/*taken input on employ details*/
for(int outer=0;outer<11;outer++){
employee[inner][outer]=read.nextLine();
}
System.out.println();
}
for(int inner=0;inner<numberOfEmployees;inner++){
employee[inner][11] = (int)(Integer.parseInt(employee[inner][5])+Integer.parseInt(employee[inner][6])
+Integer.parseInt(employee[inner][7])+Integer.parseInt(employee[inner][8])
-Integer.parseInt(employee[inner][9])-Integer.parseInt(employee[inner][10]));
}
String choice;
do{
System.out.println("do you want to search enter employee id");
String input=read.nextLine();
System.out.println("do you want to continue press yes or YES");
read.nextLine();
choice =read.nextLine();
}while(choice=="yes" || choice=="YES");
for(int inner=0;inner<numberOfEmployees;inner++){
if(employee[inner][0]=="input"){
for(int outer=0;outer<12;outer++)
System.out.print(employee[inner][outer]);
}
System.out.println();
}
}
}
答案 0 :(得分:0)
如果正确格式化问题中的代码,将更容易看出出现了什么问题。但首先要说:
不要比较这样的字符串:
choice=="yes"
然后你只需检查第一个String对象是否与第二个对象是同一个对象,在这种情况下它们永远不会。
相反,请这样:
choice.equals("yes")
或者更好,因为你永远不会冒NullPointerException风险:
"yes".equals(choice)