Question

我正在尝试使用PHP文件和JSONObject与我的远程数据库进行连接，但是代码正在滑动Response.Listener，我不知道为什么...... 这里我的Main包含Response.Listener：

Response.Listener<String> responseListener = new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    try {

                        Toast.makeText(Register.this, "Test00", Toast.LENGTH_SHORT).show();

                        JSONObject jsonObject = new JSONObject(response);
                        boolean success = jsonObject.getBoolean("success");

                        if(success)
                        {
                            Toast.makeText(Register.this, "Test01", Toast.LENGTH_SHORT).show();
                        }
                        else
                        {
                            Toast.makeText(Register.this, "Error", Toast.LENGTH_SHORT).show();
                        }

                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            };

            RegisterRequest registerRequest = new RegisterRequest(email, username, usernick, password, birthdate, gender, responseListener);
            RequestQueue queue = Volley.newRequestQueue(Register.this);
            queue.add(registerRequest);

这里是我的RegisterRequest类：

public class RegisterRequest extends StringRequest {

private static final String REGISTER_REQUEST_URL = "kameo.com.br/control/ayzac_control_signin_mobile.php";
private Map<String, String> params;

public RegisterRequest(String email, String name, String nickname, String password, String date, String gender, Response.Listener<String> listener)
{
    super(Method.POST, REGISTER_REQUEST_URL, listener, null);
    params = new HashMap<>();
    params.put("userEmail", email);
    params.put("userName", name);
    params.put("userNickname", nickname);
    params.put("userPassword", password);
    params.put("userBirth", date);
    params.put("userGender", gender);
}

@Override
public Map<String, String> getParams() {
    return params;
}
}

Answer 1

我测试了您的网址，并且出现了错误：kameo.com.br/control/ayzac_control_signin_mobile.php

此外，您需要从服务器响应中读取错误，尝试创建错误监听器：

Response.Listener<String> errorListener = new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                Log.e(TAG, "Error : " + error.getMessage());
            }
       };

并传递给RegisterRequest构造函数

使用Response和JSON的Android Studio数据库连接

1 个答案: