Question

我想将所有项目的列表与相同的companyName和companyId合并。

我需要帮助处理数据，以便它会为companyName和companyId获取具有相同值的所有数据，并将其合并到自己的数组中。

输入示例我期望的数据将在此处：

[{
    "companyName": "ABC company",
    "companyId": "123",
    "projectName": "project1",
    "levelCode": "893",
    "projectStatus": "2"

},
{
    "companyName": "ABC company",
    "companyId": "123",
    "projectName": "project2",
    "levelCode": "1386",
    "userId": "183",
    "projectStatus": "2"

},
{
    "companyName": "ABC company",
    "companyId": "123",
    "projectName": "project3",
    "levelCode": "1655",
    "userId": "183",
    "projectStatus": "1"

},
{
    "companyName": "ABC company",
    "companyId": "123",
    "projectName": "project4",
    "levelCode": "1865",
    "userId": "159",
    "projectStatus": "2"

}]

预期产出

操作所有数据之后：请注意，涉及companyName“ABC公司”的所有项目现在都合并为一个数组（项目）。

[
  {
    "companyName": "ABC company",
    "companyId": "123",
    "projects": {
      "projectName": "project1",
      "levelCode": "893",
      "projectStatus": "2"
    },
    {
      "projectName": "project2",
      "levelCode": "1386",
      "userId": "183",
      "projectStatus": "2"
    },
    {
      "projectName": "project3",
      "levelCode": "1655",
      "userId": "183",
      "projectStatus": "1"
    },
    {
      "projectName": "project4",
      "levelCode": "1865",
      "userId": "159",
      "projectStatus": "2"
    }
  }
]

Answer 1

This will work:

%dw 1.0
%output application/json
---
payload distinctBy $.companyName map ((result, IndexOfResult) -> {
    companyName: result.companyName,
    companyId: result.companyId,
    project: payload[?($.companyName == result.companyName)] map {
        projectName: $.projectName,
        levelCode: $.levelCode,
        userId: $.userId,
        projectStatus: $.projectStatus
    } 
})

Answer 2

检查出来。

%dw 1.0
%output application/json
---
payload distinctBy $.CompanyName map {
    companyName: $.companyName,
    companyID: $.companyId,
    Projects: payload map {
        projectName: $.projectName,
        levelCode: $.levelCode,
        userId: $.userId,
        projectStatus: $.projectStatus
        }
}

Answer 3

您可以使用GroupBy运算符轻松完成此操作。在这里，您需要按companyName和companyId进行分组 payload groupBy $ .companyName，companyId

请阅读以下链接，了解有关groupby运营商的详细信息。 https://docs.mulesoft.com/mule-user-guide/v/3.8/dataweave-operators#group-by

dataweave数组转换，以组合具有相同键值的数据

3 个答案: