Python3 /从列表中创建具有不同参数的多个类对象？

Question

我想创建我的班车的实例。如何从列表中为每个x数量的汽车中的参数设置？

argument_list = ['h','2','2','0','v','2','0','0'........etc]

car1 = car('h','2','2','0')
car2 = car('v','2','0','0')
car3 = car(............etc)

为每一辆车做这件事会非常糟糕：

car1 = car(*coordinate_list[0:4])
car2 = car(*coordinate_list[4:8])

Answer 1

你可以用for循环和全局变量完成这个。

class Car:
    def __init__(self, *args, **kwargs):
        print(args, kwargs)
        self.attr1 = args[0]
        self.attr2 = args[1]
        self.attr3 = args[2]
        self.attr4 = args[3]

argument_list = list(range(32)) #enough arguments for 8 cars

# the // operator guarantees integer division
num_cars = len(argument_list)//4 
car_list = []
for i in range(num_cars-1):
    # [i*4:(i+1)*4] will grab 4 items at a time from argument list
    # the asterisk before it *argument_list[i*4:(i+1)*4] unpacks the list so they can be arguments for init  
    car_list.append(Car(*argument_list[i*4:(i+1)*4]))


for car in car_list:
    print(car.attr1, car.attr2, car.attr3, car.attr4)


for i, car in enumerate(car_list):
    # accesses global variables and adds whatever variable we want by name
    globals()['car' + str(i)] = car 

print(car1.attr1)

print(car2.attr2)