Question

我返回了以下JSON对象，我想访问所有“title”值。我已经能够获得所有“页面”的新对象，但不能获得“标题”。除了正确的事情，我已经尝试了一切！这里的“类似”问题是直接的阵列访问问题。这似乎涉及嵌套数组。请帮忙！感谢。

{
    "batchcomplete": "",
    "continue": {
        "gsroffset": 15,
        "continue": "gsroffset||"
    },
    "query": {
        "pages": {
            "22989": {
                "pageid": 22989,
                "ns": 0,
                "title": "Paris",
                "index": 1
            },
            "59134": {
                "pageid": 59134,
                "ns": 0,
                "title": "Paris Commune",
                "index": 13
            },
            "61371": {
                "pageid": 61371,
                "ns": 0,
                "title": "Paris (disambiguation)",
                "index": 2
            },
            "64129": {
                "pageid": 64129,
                "ns": 0,
                "title": "Catacombs of Paris",
                "index": 11
            },
            "76286": {
                "pageid": 76286,
                "ns": 0,
                "title": "Disneyland Paris",
                "index": 15
            },
            "89106": {
                "pageid": 89106,
                "ns": 0,
                "title": "Paris–Brest–Paris",
                "index": 8
            },
            "357488": {
                "pageid": 357488,
                "ns": 0,
                "title": "Paris Saint-Germain F.C.",
                "index": 10
            },
            "868936": {
                "pageid": 868936,
                "ns": 0,
                "title": "Paris Gun",
                "index": 14
            },
            "2397134": {
                "pageid": 2397134,
                "ns": 0,
                "title": "Paris (Paris Hilton album)",
                "index": 6
            },
            "7618874": {
                "pageid": 7618874,
                "ns": 0,
                "title": "Paris syndrome",
                "index": 9
            },
            "11217925": {
                "pageid": 11217925,
                "ns": 0,
                "title": "Paris Hilton",
                "index": 7
            },
            "23528038": {
                "pageid": 23528038,
                "ns": 0,
                "title": "Paris Jackson (actress)",
                "index": 5
            },
            "30242372": {
                "pageid": 30242372,
                "ns": 0,
                "title": "Paris Agreement",
                "index": 4
            },
            "45259235": {
                "pageid": 45259235,
                "ns": 0,
                "title": "Paris Laxmi",
                "index": 12
            },
            "55340805": {
                "pageid": 55340805,
                "ns": 0,
                "title": "Paris Paris",
                "index": 3
            }
        }
    }
}

它希望我添加更多细节，但我不知道还能添加什么。

Answer 1

试试这个：

const data = //your json
const pages = data.query.pages
const titles = Object.keys(pages).map( key => pages[key].title )

存储＆＃39;页面中的值＆＃39;在变量中，然后使用Object.keys将“＆＃39;页面”中的所有键作为数组。然后使用map运算符迭代这些键，并为每个键返回属性＆＃39; title＆＃39;这个条目。

Answer 2

如果你想使用lodash / underscore，这样的东西会起作用：

const dataPages = data["query"]["pages"];
let titles = [];
_.each(dataPages, (dataPage) => titles.push(dataPage["title"]))

这应该会给你一个标题数组！

Answer 3

这使用Object.keys来枚举JSON中的页面。

"use strict"
const DATA = //your Map
const pages = DATA.query.pages; 
const keys = Object.keys(pages); // returns an array of the ID numbers that are properties in each page
let titles = [keys.length]; // initialize an output array

for(let i=0; i < keys.length; i++){
    titles[i] = pages[keys[i]].title;
};

使用javascript访问JSON对象中的数据

3 个答案: