Question

我目前发现在我的代码中无法修复无限递归的发生。

我有以下标题定义了Proces类：

#pragma once
#include <iostream>
class Proces {
    std::string name;
    int maxWaitTime;
    int timeToFinish;
    int timeWaited;
    int timeProcessed;

public:
    Proces(std::string n, int mwt = 1, int ttf = 1) :name(n), maxWaitTime(mwt), timeToFinish(ttf), timeWaited(0), timeProcessed(0) {}
    bool process(int a = 1) { timeProcessed += a; return isComplete(); }
    bool isComplete() { return timeProcessed >= timeToFinish; }
    bool wait(int a = 1) { timeWaited += a;return maxWaitReached(); }
    bool maxWaitReached() { return maxWaitTime <= timeWaited; }
    friend bool operator<(const Proces& a, const Proces& b);
    friend bool operator>(const Proces& a, const Proces& b);
    friend std::ostream &operator<<(std::ostream &output, const Proces& a);
    friend std::istream &operator>>(std::istream &input, const Proces& a);
};

然后，为了实现运营商，我有：

 #include "proces.h"

    bool operator<(const Proces & a, const Proces & b)
    {
        if (a.timeWaited != b.timeWaited)
            return a.timeWaited < b.timeWaited;
        else
            return a.maxWaitTime < b.maxWaitTime;
    }

    bool operator>(const Proces & a, const Proces & b)
    {
        return ! (a < b);
    }

    std::ostream & operator<<(std::ostream & output, const Proces & a)
    {
        output << a.naziv << " MWT:" << a.maxWaitTime << " TTC:" << a.timeToFinish << " WT:" << a.timeWaited << " TP:" << a.timeProcessed;
        return output;
    }

    std::istream & operator>>(std::istream & input,Proces & a)
    {
        input >> a.name >> a.maxWaitTime >> a.timeToFinish;
        a.timeWaited = 0;
        a.timeProcessed = 0;
        return input;
    }

这导致两个（据我所知无关）问题：

使用输出操作符导致所述无限递归发生
如果没有注释掉实现，就无法编译代码本身输入操作符的声明，因为它声称类的字段是不可访问的尽管是班上的朋友

严重级代码描述项目文件行抑制状态错误（活动）E0265成员＆＃34;进程::名称＆＃34; （在＆＃34的第4行声明; [项目路径] \ proces.h＆＃34;）无法访问aspdz2 [项目路径] \ proces.cpp

这是主要功能（＆lt;＆gt;运算符按预期工作）：

#include "proces.h"

int main() {
    Proces a{ "Glorious prces",1,2 };
    Proces b{ "Glorious prces2",2,2 };

    if (a < b)std::cout << "A is lesser" << std::endl;
    else std::cout << "B is lesser" << std::endl;

    if (a > b)std::cout << "A is greater" << std::endl;
    else std::cout << "B is greater" << std::endl;
    b.wait(-1);
    if (a < b)std::cout << "A is lesser" << std::endl;
    else std::cout << "B is lesser" << std::endl;

    //Infinite recursion happens here:
    std::cout << b << std::endl;

}

Answer 1

出现原因

严重级代码说明项目文件行抑制状态错误（活动）E0265成员＆＃34;进程::名称＆＃34; （在＆＃34的第4行声明; [项目路径] \ proces.h＆＃34;）无法访问aspdz2 [项目路径] \ proces.cpp

错误是由于在const运算符的声明中意外包含了>>关键字; 另一方面，递归发生是因为我忘了#include<string>

C ++：问题重载I / O运算符

1 个答案: