Laravel：Eloquent'超过'和'小于'

Question

我想在查询构建器中使用这样的数据库查询：

$now = new Carbon; $feed = Post::where([ ['active' => 1], ['published' => $now] ]) -> take(5) -> get() -> toArray();

我做了什么：

SELECT * FROM posts WHERE active = 1 AND published = '{$now}' LIMIT 5

但它就像：

<

如何使用<=方法制作>，>=，<>，LIKE，::where和UPDATE your_table SET displayorder = displayorder + X * C; 语句？

Answer 1

像这样使用['published','>=',$now]

$now = new Carbon;
$feed = Post::where([
    ['active', '=', '1'],
    ['published','>=',$now]
])
->take(5)
->get()
->toArray();

或使用单独的函数

$now = new Carbon;
$feed = Post::where('active', 1)->where('published','>=', $now)
->take(5)
->get()
->toArray();

Answer 2

锋

  $feed = Post::where('active','=',1)->where('published','<=',$now)->get();

Answer 3

使用此

$feed = Post::where('active',1)
->where('published','<=',$now)
->take(5)
->get()
->toArray();

请参阅手册：https://laravel.com/docs/master/queries#raw-expressions