Question

请帮帮我如何将此查询转换为codeigniter查询格式

SELECT *
FROM `table1`
LEFT JOIN `table2`
    ON table1.permission_key = table2.permission_key AND
       (table2.role_id is null || table2.role_id="1")
WHERE
    table1.section  ='abc' AND
    table1.sub_section = 'xzy';

Answer 1

您好，请尝试以下

$this->db->select('table1.*')
    ->from('table1')
    ->join('table2', 'table1.permission_key=table2.permission_key AND (table2.role_id is null OR table2.role_id="1")', 'left')
    ->where('table1.section', 'abc')
    ->where('table1.sub_section', 'xzy')
    ->result_array();

Answer 2

您可以将查询键入普通sql语句并将其传递给codeiginter函数$this->db->query();

$query = "SELECT * FROM table1 JOIN table2 ON table1.permission_key = table2.permission_key AND AND
       (table2.role_id is null || table2.role_id='1')
       WHERE table1.section  ='abc' AND table1.sub_section = 'xzy'";
$this->db->query($query);
$this->db->get();

Answer 3

试试这个。

 $wherearraydata = array('table1.section' => 'abc', 'table1.sub_section' => 'xyz');
    $this->db->select('*');
    $this->db->from('table1');
    $this->db->join('table2', 'table2.permission_key = table1.permission_key' AND (table2.role_id is null OR table2.role_id="1"));
    $this->db->where($wherearraydata); 
    $querydata = $this->db->get();

return $querydata->result_array();

Codeigniter查询：将Mysql查询转换为codeigniter查询格式

3 个答案: