Question

我试图避免cout声明。具体地，

cout<< "Enter integer 2: \n"

cin>> i

我尝试在第8个if-else语句的各个地方使用cin.ignore(j)。也就是说，来自用户选择的选项8 。

我想用最后一个复杂的方法完成这个。我在＆＃34; C ++简介＆＃34;好吧，我对先进的方法不太熟悉。

这里的目标是在原型部分下创建一个具有给定功能的计算器。

#include <iostream>
#include <math.h>
using namespace std;

int menu();
int addition (int a, int b);
int subtract (int a, int b);
int multiply (int a, int b)
int division (int a, int b);
double realDivision (double a, double b);
double quotient (double a, double b);
double remainder (double a, double b);
int factorial (int a);

int main(int argc, const char * argv[])
{
    int choice, i, j;
    choice = menu();

    if (choice == 0)
        return 0;

    cout << "Enter integer 1: \n";
    cin >> i;

    cout << "Enter integer 2: \n";
    cin >> j;

    if (choice == 1)
        cout << addition(i, j) << endl;

    else if (choice == 2)
        cout << subtract(i, j) << endl;

    else if (choice == 3)
        cout << multiply(i, j) << endl;

    else if (choice == 4)
        cout << division(i, j) << endl;

    else if (choice == 5)
        cout << realDivision(i, j) << endl;

    else if (choice == 6)
        cout << quotient(i, j) << endl;

    else if (choice == 7)
        cout << remainder(i, j) << endl;

    else if (choice == 8)
        cout << i << ", factorial = " << factorial(i) << endl;

        return 0;
     }

int menu()
{
  int choice = 10;
   while ((choice > 9) || (choice < 0))
   {     
     cout << "Enter 0 to quit\n";
     cout << "Enter 1 for addition\n";
     cout << "Enter 2 for subtraction\n";
     cout << "Enter 3 for Multiplication\n";
     cout << "Enter 4 for Division of two integers\n";
     cout << "Enter 5 for Real Division of two integers\n"    
     cout << "Enter 6 for Quotient of a division\n";
     cout << "Enter 7 for Remainder of a division\n";
     cout << "Enter 8 for Factorial of an integer\n";
     cout << "Enter 9 for Exponential of two integers\n";
     cin >> choice;

   }
    return choice;
}

int addition(int a, int b)
{
    return(a+b);
}

int subtract(int a, int b)
{
    return(a-b);
}

int multiply(int a, int b)
{
    return (a * b);
}

int division(int a, int b)
{
    return a/b;
}

double realDivision(double a, double b)
{
    return(a/b);
}

double quotient(double a, double b)
{
    return(a/b);
}

double remainder(double a, double b)
{
    return(a/b);
}

int factorial(int a)
{
    int product = 1;
    while (a > 1)
    {
        product *=a;
        a--;
    }
    return product;
}

Answer 1

您创建了一个单独的if-else语句，该语句在除了阶乘条件之外的情况下接受第二个输入。因此，如果用户仅选择阶乘/平方根/平方根之类的操作，则您的计算器只会询问用户的一个输入。你可以这样做：

if (choice == 0)
        return 0;

    cout << "Enter integer 1: \n";
    cin >> i;

    if (choice == 8)
    {
        cout << i << ", factorial = 8" << factorial(i) << endl;
        return 0;
    }
    else
    {
        cout << "Enter integer 2: \n";
        cin >> j;
    }

    if (choice == 1)
        cout << addition(i, j) << endl;

    else if (choice == 2)
        cout << subtract(i, j) << endl;

    else if (choice == 3)
        cout << multiply(i, j) << endl;

    else if (choice == 4)
        cout << division(i, j) << endl;

    else if (choice == 5)
        cout << realDivision(i, j) << endl;

    else if (choice == 6)
        cout << quotient(i, j) << endl;

    else if (choice == 7)
        cout << remainder(i, j) << endl;

        return 0;

Answer 2

如果因子选择总是8.你可以在读取第二个数字之前检查choice!=8。如果选择是8，它将跳过第二个数字部分，然后继续它将读取第二个数字和然后继续。

#include <iostream>
#include <math.h>
using namespace std;

int menu();
int addition (int a, int b);
int subtract (int a, int b);
int multiply (int a, int b)
int division (int a, int b);
double realDivision (double a, double b);
double quotient (double a, double b);
double remainder (double a, double b);
int factorial (int a);

int main(int argc, const char * argv[])
{
    int choice, i, j;
    choice = menu();

    if (choice == 0)
        return 0;

    cout << "Enter integer 1: \n";
    cin >> i;

    if(choice!=8)
    cout << "Enter integer 2: \n";
    cin >> j;

    if (choice == 1)
        cout << addition(i, j) << endl;

    else if (choice == 2)
        cout << subtract(i, j) << endl;

    else if (choice == 3)
        cout << multiply(i, j) << endl;

    else if (choice == 4)
        cout << division(i, j) << endl;

    else if (choice == 5)
        cout << realDivision(i, j) << endl;

    else if (choice == 6)
        cout << quotient(i, j) << endl;

    else if (choice == 7)
        cout << remainder(i, j) << endl;

    else if (choice == 8)
        cout << i << ", factorial = 8" << factorial(i) << endl;

        return 0;
     }

int menu()
{
  int choice = 10;
   while ((choice > 9) || (choice < 0))
   {     
     cout << "Enter 0 to quit\n";
     cout << "Enter 1 for addition\n";
     cout << "Enter 2 for subtraction\n";
     cout << "Enter 3 for Multiplication\n";
     cout << "Enter 4 for Division of two integers\n";
     cout << "Enter 5 for Real Division of two integers\n"    
     cout << "Enter 6 for Quotient of a division\n";
     cout << "Enter 7 for Remainder of a division\n";
     cout << "Enter 8 for Factorial of an integer\n";
     cout << "Enter 9 for Exponential of two integers\n";
     cin >> choice;

   }
    return choice;
}

int addition(int a, int b)
{
    return(a+b);
}

int subtract(int a, int b)
{
    return(a-b);
}

int multiply(int a, int b)
{
    return (a * b);
}

int division(int a, int b)
{
    return a/b;
}

double realDivision(double a, double b)
{
    return(a/b);
}

double quotient(double a, double b)
{
    return(a/b);
}

double remainder(double a, double b)
{
    return(a/b);
}

int factorial(int a)
{
    int product = 1;
    while (a > 1)
    {
        product *=a;
        a--;
    }
    return product;
}

如何省略＆＃34; Cout＆＃34;一个特殊的声明＆＃34; if-else＆＃34;声明？

2 个答案: