Question

如何删除findIndexInO中compareIndexes的重复来电？

const a = [
  {name: 'charlie', value: 1},
  {name: 'bravo', value: 7},
  {name: 'delta', value: 12},
  {name: 'alpha', value: 19},
]

const propEqName = propEq('name');
const findIndexInO = findIndex(__, a);
const compareIndexes = comparator((from, to) => lt(findIndexInO(propEqName(from)), findIndexInO(propEqName(to))))
const sortOnIndex = sort(compareIndexes);

const decideOrder = (...args) => sortOnIndex(args);

decideOrder('delta', 'charlie'); // ['charlie', 'delta']
decideOrder('bravo', 'alpha'); // ['bravo', 'alpha']
decideOrder('alpha', 'charlie'); // ['charlie', 'alpha']

REPL

Answer 1

怎么样

const order = addIndex(reduce)((ord, a, idx) => assoc(a.name, idx, ord), {}, a)
const decideOrder = unapply(sortBy(prop(__, order)))

？因为您已经在函数中嵌入了a。作为额外的好处，如果对您而言，您也可以这样做：

decideOrder('delta', 'alpha', 'bravo') //=> ["bravo", "delta", "alpha"]

删除Ramda函数中的重复

1 个答案: