我正在创建一个更新触发器,员工的薪水永远不会高于总统。但是,我需要将总统的薪水用于比较,以及" new"更新了员工的工资。
我最初使用from employees表中的子查询,但由于表变异问题而不得不创建一个新表。我不认为创建新表是真正实现的合理解决方案。
有没有办法可以在不创建新桌子的情况下节省总统薪水?
CREATE OR REPLACE TRIGGER prevent_salary
BEFORE UPDATE ON employees
FOR EACH ROW
declare pres_sal number(8,2);
BEGIN
select salary into pres_sal from employees_salary where job_id='AD_PRES';--employees_salary was employees but that gives mutating error
IF (:new.salary > pres_sal)
THEN UPDATE employees
SET salary = :old.salary
WHERE employee_id = :old.employee_id;
END IF;
END;
答案 0 :(得分:1)
你可以试试这个:
CREATE OR REPLACE TRIGGER prevent_salary
BEFORE UPDATE ON employees
FOR EACH ROW
declare pres_sal number(8,2);
BEGIN
select salary into pres_sal from employees_salary where job_id='AD_PRES';--employees_salary was employees but that gives mutating error
IF (:new.salary > pres_sal)
Raise_Application_Error (-20101, 'An employee''s salary couldn''t exceed president''s !');
END IF;
END;
答案 1 :(得分:1)
一种方法是在BEFORE STATEMENT
触发器中保存总统的薪水,然后在FOR EACH ROW
触发器中使用它。
“复合触发器”,至少从版本11.1开始,在一个地方提供了一种很好的方法。
以下是一个例子:
CREATE OR REPLACE TRIGGER prevent_salary
FOR UPDATE OF salary ON employees
COMPOUND TRIGGER
pres_sal NUMBER;
BEFORE STATEMENT IS
BEGIN
select salary
into pres_sal
from employees
where job_id='AD_PRES';
END BEFORE STATEMENT;
BEFORE EACH ROW IS
BEGIN
:new.salary := least(:new.salary, pres_sal);
END BEFORE EACH ROW;
END prevent_salary;