Question

例如"apple" 应删除而"dog" 不应。

例如："Dog ate my apple,so i am sad wow."

结果将是："Dog ate my ,so i am sad."

char[] skyrikliai = { ' ', '.', ',', '!', '?', ':', ';', '(', ')', '\t' };

 string[] parts = line.Split(skyrikliai, StringSplitOptions.RemoveEmptyEntries);
   foreach (string word in parts)

Answer 1

不能是最聪明的方式，但有效：

 using System.Linq;

    string line = "Dog ate my apple,so i am sad wow.";

    char[] skyrikliai = { ' ', '.', ',', '!', '?', ':', ';', '(', ')', '\t' };


    string[] parts = line.Split(skyrikliai, StringSplitOptions.RemoveEmptyEntries);

    foreach (string word in parts)
    {

        char[] letters = word.ToCharArray();

        var DisintctLetters = letters.Distinct().ToArray();

        if (letters.Length != DisintctLetters.Length)

        {
            line = line.Replace(word, "");
        }

    }
   Console.WriteLine(line);

我认为您的帖子中有拼写错误，Apple应该删除，并且应该保留Dog，如果是的话：

输出结果为：Dog ate my ,so i am sad .

Answer 2

我假设您要删除任何以指定特殊字符之一结尾的给定单词。

因此，您可以使用正则表达式：（using System.Text.RegularExpressions;）

string str = "Dog ate my apple, so I am sad wow.";
var reg = new Regex(@"\w+[.|,|!|?|:|;|(|)|\t]");
var matches = reg.Matches(str);

// access the current match with 'i' 
// keep track of how many characters were removed with 'j'
for (int i = 0, j = 0; i < matches.Count; i++)
{
    str = str.Remove(matches[i].Index - j - 1, matches[i].Length);
    j += matches[i].Length;
}

输出为：Dog ate my, so I am sad.

从文本中删除单词，但只删除包含所有不同字母的单词

2 个答案: