我将如何编码＆＃34; q退出＆＃34;？ （Python 3.6）

Question

我一直在与合作伙伴一起为课堂作业编写一个程序，而且我们一直坚持要添加一个＆＃34; q来退出＆＃34;在里面。作业是做一个猜测数字＆＃34;游戏。这是我们的代码：

import random

def get_distance(secret,guess):
    difference = abs(secret - guess)
    return difference
def point_machine(guess1,guess2):
    points_1 = 0
    points_2 = 0
    if guess1 < guess2:
        print ("Player 1 wins")
        points_1 += 1
    elif guess2 < guess1:
        print ("Player 2 wins")
        points_2 += 1
    elif guess1 == guess2:
        print ("It's a tie!")
        points_1 += 1
        points_2 += 1
    return points_1, points_2

x = 0
print ("Welcome to Guess-the-Number!")
print ("Press 'q' to quit at any time.")
name1 = input("What is player one's name?: ")
name2 = input("What is player two's name?: ")
rounds = (input("How many rounds?: "))
points_1 = 0
points_2 = 0
for i in range(int(rounds)):
    x += 1
    secret = random.randint(0,100)
    print ("Round",x)
    print ("~~~~~~~")
    guess1 = int(input(name1+", take a guess: "))
    guess1 = get_distance(secret,guess1)
    guess2 = int(input(name2+", take a guess: "))
    guess2 = get_distance(secret,guess2)
    new1,new2=point_machine(guess1,guess2)
    points_1 += new1
    points_2 += new2
    print ("The number was:",secret)
    print ("Score:",points_1,"to",points_2)

if points_1 > points_2:
    print (name1,"wins the game!")
elif points_2 > points_1:
    print (name2,"wins the game!")
elif points_1 == points_2:
    print ("It's a tie!")
    print (points_1,"to",points_2)

要求是当＆＃34; q＆＃34;在游戏过程中随时输入，它会返回到主菜单＆＃34;。

提前致谢

Answer 1

您需要在每个input（）命令中进行测试。所以而不是：

guess1 = int(input(name1+", take a guess: "))
guess1 = get_distance(secret,guess1)
guess2 = int(input(name2+", take a guess: "))
guess2 = get_distance(secret,guess2)

试试这个：

userInput = input(name1+", take a guess: ")
if userInput == "q":
    exit()

guess1 = int(userInput)
guess1 = get_distance(secret,guess1)

userInput = input(name2+", take a guess: ")
if userInput == "q":
    exit()

guess2 = int(userInput)
guess2 = get_distance(secret,guess2)

这样，用户可以随时键入＆＃34; q＆＃34;并按Enter键退出游戏。

或者，您可以定义自己的函数来代替input（）函数：

def userInput(prefix):
    a = input(prefix)
    if a=="q":
        exit()
    else:
        return a

然后：

guess1 = int(userInput(name1+", take a guess: "))
guess1 = get_distance(secret,guess1)
guess2 = int(userInput(name2+", take a guess: "))
guess2 = get_distance(secret,guess2)

Answer 2

您可以使用pythoncom，pyHook

import pythoncom, pyHook
import random

def get_distance(secret,guess):
    difference = abs(secret - guess)
    return difference

def point_machine(guess1,guess2):
    points_1 = 0
    points_2 = 0
    if guess1 < guess2:
        print ("Player 1 wins")
        points_1 += 1
    elif guess2 < guess1:
        print ("Player 2 wins")
        points_2 += 1
    elif guess1 == guess2:
        print ("It's a tie!")
        points_1 += 1
        points_2 += 1
    return points_1, points_2

def start_game():
    x = 0
    print ("Welcome to Guess-the-Number!")
    print ("Press 'q' to quit at any time.")
    name1 = input("What is player one's name?: ")
    name2 = input("What is player two's name?: ")
    rounds = (input("How many rounds?: "))
    points_1 = 0
    points_2 = 0
    for i in range(int(rounds)):
        x += 1
        secret = random.randint(0,100)
        print ("Round",x)
        print ("~~~~~~~")
        guess1 = int(input(name1+", take a guess: "))
        guess1 = get_distance(secret,guess1)
        guess2 = int(input(name2+", take a guess: "))
        guess2 = get_distance(secret,guess2)
        new1,new2=point_machine(guess1,guess2)
        points_1 += new1
        points_2 += new2
        print ("The number was:",secret)
        print ("Score:",points_1,"to",points_2)

    if points_1 > points_2:
        print (name1,"wins the game!")
    elif points_2 > points_1:
        print (name2,"wins the game!")
    elif points_1 == points_2:
        print ("It's a tie!")
        print (points_1,"to",points_2)

def OnKeyboardEvent(event):

    if event.Key in ['q', 'Q']:
        start_game()


    # return True to pass the event to other handlers
    return True

# create a hook manager
hm = pyHook.HookManager()
# watch for all input events
hm.KeyDown = OnKeyboardEvent
# set the hook
hm.HookKeyboard()
# wait forever
pythoncom.PumpMessages()

start_game()