附加代码应该为每位患者返回第一个ORDER_PROC.ORDER_INST。我在某些情况下获得了多条记录。 有关更好方法的任何建议吗? 谢谢 史蒂夫
SELECT DISTINCT
ORDER_PROC.PAT_ENC_CSN_ID as ordercsn, Min(ORDER_PROC.ORDER_INST) as
CodeStatus_Datetime, CLARITY_SER.PROV_NAME as CodeStatus_OrderProvider
FROM
ORDER_PROC with(nolock) , ORDER_METRICS with(nolock) , CLARITY_SER
with(nolock)
WHERE
ORDER_PROC.ORDER_PROC_ID = ORDER_METRICS.ORDER_ID AND
ORDER_METRICS.ORDERING_PROV_ID = CLARITY_SER.PROV_ID AND
--ORDER_PROC.REASON_FOR_CANC_C IS NULL AND
(ORDER_PROC.PROC_CODE = 'COD1' OR
ORDER_PROC.PROC_CODE = 'COD2' OR
ORDER_PROC.PROC_CODE = 'COD3'
)
GROUP by
ORDER_PROC.PAT_ENC_CSN_ID, ORDER_PROC.ORDER_INST,CLARITY_SER.PROV_NAME
答案 0 :(得分:1)
使用ROW_NUMBER()
为每位患者创建分区
SELECT *
FROM (
SELECT OP.PAT_ENC_CSN_ID as ordercsn,
OP.ORDER_INST,
CodeStatus_Datetime,
CS.PROV_NAME as CodeStatus_OrderProvider,
ROW_NUMBER() OVER (PARTITION BY OP.PAT_ENC_CSN_ID
ORDER BY OP.ORDER_INST) as rn
FROM ORDER_PROC OP
JOIN ORDER_METRICS OM
OP.ORDER_PROC_ID = OM.ORDER_ID
JOIN CLARITY_SER CS
OM.ORDERING_PROV_ID = CS.PROV_ID
WHERE
OP.PROC_CODE IN ('COD1','COD2','COD3')
) as T
WHERE rn = 1