仅使用PHP

Question

这可能已被多次询问，但我无法找到解决方案。

这是我的阵列：

$request=Array ( 
        [0] => Array ( [staName] => Auditorium Stravinsky 2m2c ) 
        [1] => Array ( [staName] => Geneva Arena ) 
        [2] => Array ( [staName] => Les Docks ) 
        [3] => Array ( [staName] => Kheops ) 
    )

我需要输出如下JSON：

"Auditorium Stravinsky 2m2c ","Geneva Arena","Les Docks","Kheops"

我目前的代码如下：

    foreach($request as $value)
    {
        $names[]=$value;
    }

    $jsonValue = json_encode(array_values($names));

    print_r($jsonValue);

我目前的输出如下JSON格式：

[{"staName":"Auditorium Stravinsky 2m2c "},{"staName":"Geneva Arena"},{"staName":"Les Docks"},{"staName":"Kheops"}]

如何阻止“staName”被排除？

非常感谢，请考虑我的帖子，因为这只是我在本网站上发表的第二篇文章。

Answer 1

<?php

$request=Array (
        0 => Array ( 'staName' => 'Auditorium Stravinsky 2m2c' ) ,
        1 => Array ( 'staName' => 'Geneva Arena' ) ,
        2 => Array ( 'staName' => 'Les Docks' ) ,
        3 => Array ( 'staName' => 'Kheops' )
    );


$newArray=array();
for($i=0;$i<count($request);$i++){
    $newArray[$i]=$request[$i]['staName'];
}

$newArray=json_encode($newArray,true);
print_r($newArray);

输出是合并的json：

["Auditorium Stravinsky 2m2c","Geneva Arena","Les Docks","Kheops"]

Answer 2

你可以通过以下方式实现这一点 的代码

$a = array();
foreach($request as $key =>$val){
  foreach($val as $k => $v){
   $a[] = $v;
  }
}
print_r(json_encode($a));

检查此演示link

<强>输出

["Auditorium Stravinsky 2m2c","Geneva Arena","Les Docks","Kheops"]

Answer 3

所有array定义中的第一个都不正确。并且您的输出是简单字符串而不是JSON

<?php

$request=Array ( 
        0 => Array ( 'staName' => 'Auditorium Stravinsky 2m2c' ), 
        1 => Array ( 'staName' => 'Geneva Arena' ) ,
        2 => Array ( 'staName' => 'Les Docks' ) ,
        3 => Array ( 'staName' => 'Kheops' ) 
    );

    $name = '';
    foreach($request as $value)
    {
        foreach($value as $value2)
        {
            $name = $name . ' ' . $value2;
        }

    }
    echo $name;

输出

Auditorium Stravinsky 2m2c Geneva Arena Les Docks Kheops