Question

我有网络应用程序，我想部署到weblogic，我添加了UrlRewriteFilter

<filter>
    <filter-name>UrlRewriteFilter</filter-name>
    <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
    <init-param>
        <param-name>logLevel</param-name>
        <param-value>DEBUG</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>UrlRewriteFilter</filter-name>
    <url-pattern>/*</url-pattern>
    <dispatcher>REQUEST</dispatcher>
    <dispatcher>FORWARD</dispatcher>
</filter-mapping>

我还定义了以下规则：

<rule>
    <note>the context root should be redirected by appending a / to the path</note>
    <from>%{context-path}</from>
    <to type="redirect">%{context-path}/</to>
</rule>

我想以与Tomcat中可能类似的方式重定向Weblogic中的上下文根。

有关详细信息，请参阅Redirect context root in Weblogic

当我部署应用程序并尝试访问http://localhost:7001/my-application时，我得到：

org.tuckey.web.filters.urlrewrite.Conf DEBUG: now initialising conf
org.tuckey.web.filters.urlrewrite.NormalRule ERROR: Rule Rule 0 had error: from (%{context-path}) is an invalid expression - java.util.regex.PatternSyntaxException: Illegal repetition near index 0
%{context-path}
^ 
org.tuckey.web.filters.urlrewrite.RuleBase ERROR: from (%{context-path}) is an invalid expression - java.util.regex.PatternSyntaxException: Illegal repetition near index 0
%{context-path}
^
org.tuckey.web.filters.urlrewrite.RuleBase DEBUG: loaded rule Rule 0 (%{context-path}, %{context-path}/ 0)
org.tuckey.web.filters.urlrewrite.NormalRule DEBUG: failed to load rule
org.tuckey.web.filters.urlrewrite.Conf DEBUG: conf status false
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: inited with 1 rules
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter DEBUG: conf is NOT ok
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter ERROR: Conf failed to load

我也理解我的过滤器有<url-pattern>/*</url-pattern>，因此它会捕获两个网址（带斜线和不带斜线）

是否有可能实现我对http://www.tuckey.org/urlrewrite/

所描述的内容

如果是，怎么样？

如果不是，为什么？

Answer 1

您的 <from> 标记不正确。希望这会有所帮助

如果 context-path "myApp"

<rule>
    <from>^(.*)$</from>
    <to type="redirect" context="myApp">$1/</to>
</rule>

如果 context-path "" ，即 empty ，那么您不需要编写任何规则以将请求转发到上下文，因为默认情况下请求将转发到默认上下文

使用UrlRewriteFilter

1 个答案: