根据字典将选择的文件类型移动到新目录

时间:2017-11-16 13:11:07

标签: python python-3.x

我正在尝试根据嵌套字典将特定文件类型移动到新目录。

例如,(为了分隔视频和照片文件)将config[key1][other_file]中定义的媒体文件移动到OTHERMEDIA,用于各自文件夹中的每个相机型号:

001__=d5
    OTHERMEDIA                                   #move files to here
    IMAGES
        [mix of mediafiles in subdirectories]    #move files from here
002__=alpha9
    OTHERMEDIA                                   #move files to here
    IMAGES
        [mix of mediafiles in subdirectories]    #move files from here

代码提供shutil.move(os.path.join(root,files), os.path.join(destinationpath,files))。我做错了什么?

import shutil
import os
config = {
    'd5': {},
    'alpha9': {},
    'g7': {},
}
config['d5']['other_file'] = ('avi', 'AVI')
config['alpha9']['other_file'] = ('jpg', 'JPG')
config['g7']['other_file'] = ('mp4', 'MP4')

destinationpath = 'OTHERMEDIA'
root = os.getcwd()
for camID in config:
    for dir in next(os.walk(root))[1]:
        if dir.endswith(camID):
            for path, dirs, files in os.walk(os.path.join(root, dir)):
                for f in files:
                    if any([f.lower().endswith(x) for x in config[camID]["other_file"]]):
                        os.path.join(path, f). files, os.path.join(destinationpath,files)

1 个答案:

答案 0 :(得分:0)

当你应该os.path.join(path, files)时,你正在做os.path.join(path, f)files是整个可迭代的; f是特定文件。

此外,另外,由于您正在查看f.lower(),因此您无需将其与文件扩展名的大写版本进行比较。