循环使用RxSwift

时间:2017-11-16 11:07:14

标签: ios swift reactive-programming rx-swift

我是Reactive Programming的新手,我有一个很大的问题,我不能单独解决......我需要上传几个视频资产并按顺序上传,但我不知道该怎么做它,我有一组PHAssets,我试图通过每个元素迭代并通过网络发送它 这是我的代码到目前为止的评论:

for item in items {
                    let fileName = item.media.localIdentifier

                    //Observable to generate local url to be used to save the compressed video
                    let compressedVideoOutputUrl = videoHelper.getDocumentsURL().appendingPathComponent(fileName)

                    //Observable to generate a thumbnail image for the video
                    let thumbnailObservable =  videoHelper.getBase64Thumbnail(myItem: item)

                    //Observable to request the video from the iPhone library
                    let videoObservable = videoHelper.requestVideo(myItem: item)

                        //Compress the video and save it on the previously generated local url
                        .flatMap { videoHelper.compressVideo(inputURL: $0, outputURL: compressedVideoOutputUrl) }
                    //Generate the thumbnail and share the video to send over the network
                    let send = videoObservable.flatMap { _ in thumbnailObservable }
                        .flatMap { api.uploadSharedFiles(item, filename: fileName, base64String: $0) }

                    //subscribe the observable
                    send.subscribe(onNext: { data in
                        print("- Done chain sharing Video -")
                    },
                                   onError: { error in
                                    print("Error sharing Video-> \(error.localizedDescription)")
                    }).disposed(by: actionDisposeBag)

                }

2 个答案:

答案 0 :(得分:4)

如果要在flatMap中逐个上传项目,请使用枚举

编辑:枚举在您需要知道元素的索引时很有用,否则只有flatMap一个参数就可以了。

Observable.from(items)
    .enumerated()
    .flatMap() { index, item -> Observable<Item> in
        return uploadItem(item)
    }
    .subscribe(onNext: { print($0) })
    .disposed(by: disposeBag)

答案 1 :(得分:2)

使用集合元素和 .flatMap()对现有代码进行观察 -

const argv = require('minimist')(process.argv.slice(2));
const csv = argv.file;