Question

我有一张如下表，表名是 js_skills_achievements

id   skill1  skill2  skill3  skill4
1     java    php    html    android
2     php     java   jquery  html
3     sql     php    html    jquery

当admin搜索键是“nersupalli中的java开发人员”

时

我的查询在下面

SELECT *
FROM `js_skills_achievements`
WHERE `skill1`  LIKE '%java developer in nersupalli%'
   OR `skill2`  LIKE '%java developer in nersupalli%'
   OR `skill3`  LIKE '%java developer in nersupalli%'
   OR `skill4`  LIKE '%java developer in nersupalli%'
ORDER BY id DESC
LIMIT 10

它不适合我。我的要求是我需要显示所有java记录。这里共有2条java记录。即id1，id2。但我得到空行。

仅限以下方式

SELECT *
FROM `js_skills_achievements`
WHERE `skill1`  LIKE '%java%'
   OR `skill2`  LIKE '%java%'
   OR `skill3`  LIKE '%java%'
   OR `skill4`  LIKE '%java%'
ORDER BY id DESC
LIMIT 10

我需要基于字符串指定的关键字搜索。你能帮忙吗？非常感谢。谢谢

Answer 1

执行此操作有点难看的方法是反转你喜欢的子句并将你的字符串与列匹配

SELECT 
  * 
FROM
  js_skills_achievements 
WHERE 'java developer in nersupalli' LIKE CONCAT('%',skill1,'%')
  OR 'java developer in nersupalli' LIKE CONCAT('%',skill2,'%')
  OR 'java developer in nersupalli' LIKE CONCAT('%',skill3,'%')
  OR 'java developer in nersupalli' LIKE CONCAT('%',skill4,'%')
  OR skill1  LIKE '%java developer in nersupalli%'
  OR skill2  LIKE '%java developer in nersupalli%'
  OR skill3  LIKE '%java developer in nersupalli%'
  OR skill4  LIKE '%java developer in nersupalli%'
ORDER BY id DESC 
LIMIT 10

Demo

Answer 2

在您的文件中添加全文

ALTER TABLE `js_skills_achievements` ADD FULLTEXT(`skill1`);
ALTER TABLE `js_skills_achievements` ADD FULLTEXT(`skill2`);
ALTER TABLE `js_skills_achievements` ADD FULLTEXT(`skill3`);
ALTER TABLE `js_skills_achievements` ADD FULLTEXT(`skill4`);

然后运行此查询

SELECT * FROM js_skills_achievements
WHERE MATCH(skill1,skill2,skill3,skill4) AGAINST ('java developer in nersupalli');

Answer 3

您可以在空格上爆炸搜索字符串

$words = explode ( ' ' , $string);

搜索skill1中的所有单词。所有技巧2等等。

Answer 4

其他答案更具技术性，可能更优化，但是如果您希望完全控制查询，例如将OR更改为AND以及类似的内容，您可以用文字拆分查询并手动构建：

//your search query
$query = 'java developer in nersupalli';

//in case you want to add more skills later
$skills = ['skill1', 'skill2', 'skill3', 'skill4'];

//split your query in an array of words
$words = explode(' ', $query);

//build the sql
$condOuter = '';
foreach($skills as $skill){
    $condInner = '';
    foreach($words as $word){
        $condInner .= " OR `$skill` LIKE '%$word%'";
    }
    $condInner = substr($condInner, 4);
    $condOuter .= " OR ($condInner)";
}
$condOuter = substr($condOuter, 4);
$sql = 'SELECT * FROM `js_skills_achievements` WHERE ' . $condOuter . ' ORDER BY id DESC LIMIT 10;';

Answer 5

SELECT *
FROM `js_skills_achievements`
WHERE '%java developer in nersupalli%' LIKE CONCAT('%',skill1,'%')
   OR '%java developer in nersupalli%' LIKE CONCAT('%',skill2,'%')
   OR '%java developer in nersupalli%' LIKE CONCAT('%',skill3,'%')
   OR '%java developer in nersupalli%' LIKE CONCAT('%',skill4,'%')
ORDER BY id DESC
LIMIT 10;

SELECT QUERY LIKE仅包含字符串中的特定单词

5 个答案: