Question

$run = $dbh->prepare($query);

echo $query;
//if($run->execute()) {

     if($run->rowCount() > 0) {

         $result = $run->fetchAll(PDO::FETCH_ASSOC);
         $i = 0;
         while($i < count($result)) {

             for($e=0; $e < count($result); $e++) {

                 $result[$e] = str_replace('&Ntilde;','Ñ', str_replace('&ntilde;','ñ', $result[$e]));
                  $i++;
             }                    
         }
         return $result;
     } else {
           return array('error'=> TRUE, 'message'=> 'No result found.','query'=> $query);
     }
//}

我有这个查询，查询中的echo是：

CALL `select_date`('2016-01-01', '2016-01-31')

select_date的位置：

CREATE DEFINER=`root`@`localhost` PROCEDURE `select_date`(

param1 varchar(64),
param2 varchar(64)

)
BEGIN


declare v_max int default 0;
declare v_counter int default 0;
  start transaction;
  set v_max = (SELECT COUNT(*)
  FROM transaction_detail4
  WHERE 
    transaction_date >= param1 AND 
    transaction_date <= param2);



  while v_counter < v_max do
    # random query
SELECT *
  FROM transaction_detail4
  WHERE 
    transaction_date >= param1 AND 
    transaction_date <= param2 GROUP BY transaction_id LIMIT v_counter , 1000;

    set v_counter = v_counter + 1000;
  end while;
  commit;



END

我假设它将循环并返回循环中的所有数据但它只给我1000意味着只获得第一次迭代。因为select应返回49k +记录。

如何从循环选择

返回所有数据

在循环中选择只返回1 resullt php pdo

0 个答案: