Question

我是PL / pgSQL的新手，所以这对我来说是一种反复试验。我试图创建一个空白函数，在调用时会填充表格。以下是我到目前为止的情况：

create or replace function counties()
returns table(code varchar(16), county varchar(50), count int) as $$
DECLARE
    new_version varchar(50) := concat('sometext', max(REGEXP_REPLACE(COALESCE(schema_name, '0'), '[^0-9]*' ,'0')::integer), 'sometext') from information_schema.schemata where schema_name like 'gcversa%';
    old_version varchar(50) := concat('sometext', max(REGEXP_REPLACE(COALESCE(schema_name, '0'), '[^0-9]*' ,'0')::integer)-2, 'sometext') from information_schema.schemata where schema_name like 'gcversa%';
BEGIN RETURN QUERY
    with cte_current as (select distinct a.code as code, b.countyname as county from old_version a, public.counties b 
                 where st_intersects(a.geom,b.geom) = True group by a.code, b.countyname),

         cte_new     as (select distinct a.code as code, b.countyname as county from new_version a, public.counties b 
                 where st_intersects(a.geom,b.geom) = True group by a.code, b.countyname),


        cte_union as (select code, county from cte_current
        union all
        select code, county from cte_new)

    select code,county, count(*) as count
    from cte_union
    group by code, county
    Having count (*) <> 2;
END;
$$
LANGUAGE plpgsql;

我声明的两个变量是引用和连接两个PostgreSQL模式，然后我试图将这些变量插入到CTE中，以便将它们组合在一起。我正确地执行了函数，但是当我调用select counties()时，我收到此错误：

ERROR:  relation "old_version" does not exist
LINE 1: ...tinct a.code as code, b.countyname as county from old_versio...

那么，它没有拿起我声明的变量，有什么建议吗？

更新 Per Vao Tsun的建议我使用了动态SQL和format（）函数。以下是最终工作模型的样子：

drop function counties();

create or replace function counties()
returns table(code varchar(16), county varchar(50), count bigint) as $$
DECLARE
    new_version_number varchar(50) := concat('gcversa00', MAX("versionnumber")) from "gcdefault"."versionhistory";
    old_version_number varchar(50) := concat('gcversa00', MAX("versionnumber"-2)) from "gcdefault"."versionhistory";
BEGIN RETURN QUERY EXECUTE
format(
    'with cte_current as (select distinct a.code as code, b.countyname as county from %I.servicearea a, public.counties b 
                 where st_intersects(a.geom,b.geom) = True group by a.code, b.countyname),

         cte_new     as (select distinct a.code as code, b.countyname as county from %I.servicearea a, public.counties b 
                 where st_intersects(a.geom,b.geom) = True group by a.code, b.countyname),


        cte_union as (select code, county from cte_current
        union all
        select code, county from cte_new)

    select code,county, count(*) as count
    from cte_union
    group by code, county
    Having count (*) <> 2', new_version_number, old_version_number
    );
END;
$$
LANGUAGE plpgsql;

Answer 1

你需要动态的SQL，例如：

DeleteColumnsAndCharts wtemp.Sheets("Graphs").Range("A:X")

输入结束时的PL / pgSQL语法错误

1 个答案: