Question

class PaymentMethod extends Model
{
     ....

    public function user()
    {
        return $this->belongsTo(User::class, 'user_id', 'id');
    }
    ...
}

class User extends Authenticatable
{
    ...

    public function payment_methods()
    {
        return $this->hasMany(PaymentMethod::class, $this->getForeignKey())->orderBy('created_at', 'desc');
    }

    public function default_payment_method()
    {
        return $this->hasOne(PaymentMethod::class, 'id', 'default_payment_method_id');
    }


    ...
}

在视图中

@if($user -> getDefautPaymentMethod()->type == PaymentMethod::PAYPAL_ACCOUNT)
    <div><strong>Paypal: </strong> {{$user -> getDefautPaymentMethod()-> paypal_email}}</div>
@else
    <div><strong>Card: </strong>{{$user -> getDefautPaymentMethod()-> card_brand}} **** **** **** {{$user -> getDefautPaymentMethod()-> card_last_four}}</div>
@endif

这项工作很好。并为用户输出默认付款方式。

但我不想为用户输出所有付款方式。并且对于每个方法输出标签，如果这是用户的默认值。

我不希望在cicle

中使用DB :: RAW或子查询

    @foreach($user->payment_methods()->get() as $payment_method)
        @if($payment_method ->type == PaymentMethod::PAYPAL_ACCOUNT)
            <div><strong>Paypal: </strong> {{$payment_method -> paypal_email}}</div>
        @else
            <div><strong>Card: </strong>{{ $payment_method -> card_brand }} **** **** **** {{$payment_method -> card_last_four}}</div>
        @endif
    @endforeach

如果方法默认，如何影响此cicle和模型代码输出？

Answer 1

您可以循环使用付款方式，并将ID与默认付款方式ID进行比较。他们可以匹配，你知道它是默认的。

@foreach ($user->payment-methods()->get() as $payment_method)
    <div>
        @if ($user->get_default_payment_method()->id === $payment_method->id)
            <strong>Default Payment Method</strong>
        @endif
        {{ $payment_method }}
    </div>
@endforeach

Answer 2

我找到了解决方案：

{{1}}

laravel雄辩标记对象的关系

2 个答案: