Question

我有以下SQL查询：

 select count(t.id) from Tickets t 
    where t.IsPaid = 1 and t.Price_id = (select price.Id from Prices price 
            where price.Product_id = '7E67DAFB-C819-4715-830A-7C89EC986E4F' AND price.Quantity > (select count(t1.Id) from Tickets t1 
                where t1.IsPaid = 1 AND t1.Price_id IN (select pr.Id from Prices pr
                    where price.Product_id = pr.Id)))

问题是：如何从我的代码的这一部分获取具有最小值price.Price1字段的行？

(select price.Id from Prices price 
            where price.Product_id = '7E67DAFB-C819-4715-830A-7C89EC986E4F' AND price.Quantity > (select count(t1.Id) from Tickets t1 
                where t1.IsPaid = 1 AND t1.Price_id IN (select pr.Id from Prices pr
                    where price.Product_id = pr.Id)))

我希望由于我的代码的第二部分将只是ONE行的Id。现在这个代码总是给我所有的价格。这是主表Database structure and relations

中的关系

我尝试了不同的方法：

(select price.Id, MIN(Price1) from Prices price 
        where price.Product_id = '7E67DAFB-C819-4715-830A-7C89EC986E4F' AND price.Quantity > (select count(t1.Id) from Tickets t1 
            where t1.IsPaid = 1 AND t1.Price_id IN (select pr.Id from Prices pr
                where price.Product_id = pr.Id)) Group by Id)

但结果是：Result with MIN function

价格表中的数据示例：Prices table

票证表中的数据示例：Tickets table

Answer 1

我认为你想要实现的目标：对于给定的产品ID，找到可用的未付票据的最低价格，然后显示可用的票数

如果这是正确的：

SELECT isnull(ticket_count, 0) AS ticket_count
FROM
(
        SELECT * 
        FROM (SELECT Price_Id, MIN(Price1) OVER (Partition By Product_id) min_price from Prices) x
        WHERE min_price=Price1
    ) p
    JOIN
    (
        SELECT COUNT(Id) ticket_count, Price_Id FROM Tickets WHERE IsPaid=1 GROUP BY Price_Id
    ) t ON p.Price_Id=t.Price_Id 
WHERE p.Quantity > t.ticket_count

Answer 2

问题是：如何获得具有最小价格价值的行。价格1 我这部分代码的字段？

简单：

(select TOP 1 price.Id 
  from Prices price 
  where price.Product_id = '7E67DAFB-C819-4715-830A-7C89EC986E4F' 
  AND price.Quantity > (
    select count(t1.Id) 
    from Tickets t1 
    where t1.IsPaid = 1 
    AND t1.Price_id IN (select pr.Id from Prices pr where price.Product_id = pr.Id)
  )
ORDER BY price.Price1 ASC
)

SQL，从子查询中选择具有最小字段值的一行

2 个答案: