Question

我需要使用函数编写代码，将所有符号计数到字典中（包括空格，逗号等）和另一个函数来打印至少一次进入元组的所有元素（即给出＆＃34; Hello world＆＃34 ;输出=（＆＃39; h＆＃39;，＆＃39; e＆＃39;，＆＃39; l＆＃39;，＆＃39; o＆＃39;，＆＃39;＆＃39;，＆＃39; w＆＃39;，＆＃39; r＆＃39;，＆＃39; d＆＃39;）这是我的代码到目前为止：

def frequency(word):
  dict = {}
  for el in word:
     el = el.lower()
     if el in dict and not "":
         dict[el] += 1
     elif el not in dict and not "":
         dict[el] = 1
  for k,v in dict.items():
    print(k + ":" + str(v))

def different_symbols(word):
  dict={}
  for el in dict:
      if el not in dict:
          dict[el] = el
      elif el in dict:
         print(el)

frequency("Hello world!")
different_symbols("Hello world!")

Answer 1

使用Counter.most_common()测量频率，使用set()测量唯一字符。如果您特别希望dict和tuple输入结果：

from collections import Counter

def frequency(word):
    letters = Counter(word).most_common()
    letters_dict = {k: v for k, v in letters}
    return letters_dict

def different_symbols(word):
    return tuple(set(word))

print(frequency("Hello World!"))
# {'l': 3, 'o': 2, 'H': 1, 'e': 1, ' ': 1, 'w': 1, 'r': 1, 'd': 1}

print(different_symbols("Hello World!"))
# ('d', ' ', 'r', 'l', 'H', 'e', 'o', 'w') order is completely random

将符号打印成元组

1 个答案: