如何将来自多个Google工作表(在一个Google工作表中)的动态内容转换为相同的html表单?
在下面的代码中,我从主工作表中动态创建html表单。我想从补充表中添加表单选择。我无法将form.select作为一个html表单的一部分。
编辑:(1)更新了var html以包含每行的div。 (2)将表单和表格html直接移动到html页面。表单值仍未正确排列。我应该使用HTML模板吗?
<head>
<script type="text/javascript">
function setPageValues () {
//this is working as intended
google.script.run.withSuccessHandler(displayForm).getValuesFromSS();
}
function displayForm (values) {
var colsUsed = [4,5,0,13,15,16,17,18]; //sheet cols for form
var html = "<form><table border=0 width=90%>"; //start the form
//HERE IS THE ISSUE: gets range no problem, but html form is wrong.
//setting return value "html +=" doesn't work!
google.script.run.withSuccessHandler(displayPick).getValuesForRngName('CategoryRole');
//make the rest of the table (this all works fine)
for (var j = 0; j < colsUsed.length; j++){
colUsed = colsUsed[j]
html += "<div id=row><tr><th align=right>" + values[0][colUsed] + ":* </th>";
html += "<td><input></input type=text></td></tr></div>";
}
//close out the table and set the value (this all works fine)
html += "<tr><td></td><td><input type=submit></td></tr></form></table>";
html += "<i>* required form data.</i>";
document.getElementById("forminfo").innerHTML = html;
}
//building the pick list works just fine. results not correct in html
//tried to "return html;" but this didn't work!
function displayPick (values) {
var rows = 10000;
var catUsed = "34-31 21: Supplier";
//find limit of column values
for (var i = 0; i < rows; i++) {
if (values[i] == '') {
var rows = i;
break;
}
}
//build the select field description, and set selected option
html = "<div id=row><tr><th align=right>" + values[0] + ":* </th><td><select>";
for (var i = 1; i < rows; i++) {
if (values[i] == catUsed) {
html += "<option selected>" + values[i] + "<option>";
} else {
html += "<option>" + values[i] + "<option>";
}
}
html += "</select></td></tr></div>";
document.getElementById("formpick").innerHTML = html;
}
</script>
</head>
<body onload="setPageValues()">
<form><table border=0 width=90%>
<div id="formpick"></div>
<div id="forminfo"></div>
</table></form>
</body>
答案 0 :(得分:0)
在您的项目中放置一个函数,用&#34; openById&#34;;打开其他电子表格。然后使用google.script.run.withSuccessHandler(functionName)将数据返回到表单;