Need help with extracting the firstname, middlename and lastname from a
freetext fullname. How to extract them out with all these formats?
Need to figure out how to handle format 2,5,9,7
--fullname sample data
DECLARE @name TABLE
(fullname VARCHAR(100))
INSERT INTO @name SELECT
'Malone,Susan M' UNION ALL SELECT --1
'Conn,Chris G' UNION ALL SELECT --2
'Van Pess,Wen B' UNION ALL SELECT --3
'DESHPANDE, ANN W.' UNION ALL SELECT --4
'Asif,LEE' UNION ALL SELECT --5
'CERVANTES MANDY'UNION ALL SELECT --6
'Bill, Dave' UNION ALL SELECT --7
'SMITH,ANN M' UNION ALL SELECT --8
'BHULLER, MATT' UNION ALL SELECT --9
'KIM (DAUM), GAIL' UNION ALL SELECT --10
'John.Mills'--11
DECLARE @DELIMITER1 varchar(5), @DELIMITER2 varchar(5), @DELIMITER3
varchar(5),@MAX_LENGTH int
SET @DELIMITER1 = ','
SET @DELIMITER2 = ' '
SET @MAX_LENGTH = 50
--LastName
SELECT fullname,
case when
CHARINDEX(@DELIMITER2, fullname) >=1
then replace(SUBSTRING(fullname, 1, CHARINDEX(@DELIMITER2, fullname)
),',','')--replace to empty string if contains a ","
when
CHARINDEX(@DELIMITER2, fullname) =0
then replace(SUBSTRING(fullname, 1, CHARINDEX(@DELIMITER1, fullname)
),',','')--replace to empty string if contains a ","
else null
end as Lastname,
--Middle Name
CASE
-- Middle fullname follows two-fullname first fullnames like Mary Ann
WHEN LEN(SUBSTRING(fullname, CHARINDEX(@DELIMITER1,fullname)+
2,@MAX_LENGTH)) - LEN(REPLACE(SUBSTRING(fullname,
CHARINDEX(@DELIMITER1,fullname)+ 2,@MAX_LENGTH), @DELIMITER2, '')) > 0
--when len is greater than 0
THEN SUBSTRING(fullname, LEN(fullname) - CHARINDEX(@DELIMITER2,
REVERSE(fullname))+2, @MAX_LENGTH)
ELSE NULL
END AS Middlefullname,
--First Name
CASE
-- Count the number of @DELIMITER2. Choose the string between the
WHEN LEN(SUBSTRING(fullname, CHARINDEX(@DELIMITER1,fullname)+
2,@MAX_LENGTH)) - LEN(REPLACE(SUBSTRING(fullname,
CHARINDEX(@DELIMITER1,fullname)+ 2,@MAX_LENGTH), @DELIMITER2, '')) > 0 --
--when len is greater than 0
Then replace(ltrim(SUBSTRING(fullname, CHARINDEX(@DELIMITER1,fullname)+
1,
---need help here
(LEN(SUBSTRING(fullname, CHARINDEX(@DELIMITER1,fullname)+ 2,@MAX_LENGTH))-
LEN(SUBSTRING(fullname, LEN(fullname) - CHARINDEX(@DELIMITER2,
REVERSE(fullname))+2, @MAX_LENGTH))))),'-','') --replace the "-" to empty
string
ELSE ltrim(SUBSTRING(fullname,CHARINDEX(@DELIMITER1,fullname)+
1,@MAX_LENGTH))--trimmed leading spaces
END AS Firstname
FROM @name
order by fullname
答案 0 :(得分：0)
连接＆＃34;名称部分＆＃34;的第一个逻辑带点。请注意我的评论。
--fullname sample data
DECLARE @name TABLE
(nameid int identity, fullname VARCHAR(100))
INSERT INTO @name SELECT
'Malone,Susan M' UNION ALL SELECT --1
'Conn,Chris G' UNION ALL SELECT --2
'Van Pess,Wen B' UNION ALL SELECT --3
'DESHPANDE, ANN W.' UNION ALL SELECT --4
'Asif,LEE' UNION ALL SELECT --5
'CERVANTES MANDY'UNION ALL SELECT --6
'Bill, Dave' UNION ALL SELECT --7
'SMITH,ANN M' UNION ALL SELECT --8
'BHULLER, MATT' UNION ALL SELECT --9
'KIM (DAUM), GAIL' UNION ALL SELECT --10
'John.Mills';--11
select original = fullname, prepped = dotted.fn, total.spaces
from @name
cross apply (values (patindex('%(%),%',fullname),fullname)) prep1(x,fn) -- check for parentheses:
cross apply (values ( -- remove parentheses if they exist, replace commas w/ dots, dots w/ spaces:
case
when prep1.x > 1 then substring(fn,1,x-1) + substring(fn,charindex(',',fn,x)+1,8000)
else replace(replace(fn, ',', '.'),'.',' ')
end)) prep(fn)
cross apply (values (replace(rtrim(ltrim(replace(prep.fn,' ',' '))),' ',' '))) clean(fn)
cross apply (values (len(clean.fn)-len(replace(clean.fn,' ','')))) total(spaces) -- count spaces
cross apply (values (replace(clean.fn, ' ','.'))) dotted(fn); -- replace spaces with dots
返回
original prepped spaces
------------------------ -------------------- -------
Malone,Susan M Malone.Susan.M 2
Conn,Chris G Conn.Chris.G 2
Van Pess,Wen B Van.Pess.Wen.B 3
DESHPANDE, ANN W. DESHPANDE.ANN.W 2
Asif,LEE Asif.LEE 1
CERVANTES MANDY CERVANTES.MANDY 1
Bill, Dave Bill.Dave 1
SMITH,ANN M SMITH.ANN.M 2
BHULLER, MATT BHULLER.MATT 1
KIM (DAUM), GAIL KIM.GAIL 1
John.Mills John.Mills 1
其余的可以使用如下的解析名来完成：
--fullname sample data
DECLARE @name TABLE
(nameid int identity, fullname VARCHAR(100))
INSERT INTO @name SELECT
'Malone,Susan M' UNION ALL SELECT --1
'Conn,Chris G' UNION ALL SELECT --2
'Van Pess,Wen B' UNION ALL SELECT --3
'DESHPANDE, ANN W.' UNION ALL SELECT --4
'Asif,LEE' UNION ALL SELECT --5
'CERVANTES MANDY'UNION ALL SELECT --6
'Bill, Dave' UNION ALL SELECT --7
'SMITH,ANN M' UNION ALL SELECT --8
'BHULLER, MATT' UNION ALL SELECT --9
'KIM (DAUM), GAIL' UNION ALL SELECT --10
'John.Mills';--11
with clean as
(
select original = fullname, prepped = dotted.fn, total.spaces
from @name
cross apply (values (patindex('%(%),%',fullname),fullname)) prep1(x,fn) -- check for parentheses:
cross apply (values ( -- remove parentheses if they exist, replace commas w/ dots, dots w/ spaces:
case
when prep1.x > 1 then substring(fn,1,x-1) + substring(fn,charindex(',',fn,x)+1,8000)
else replace(replace(fn, ',', '.'),'.',' ')
end)) prep(fn)
cross apply (values (replace(rtrim(ltrim(replace(prep.fn,' ',' '))),' ',' '))) clean(fn)
cross apply (values (len(clean.fn)-len(replace(clean.fn,' ','')))) total(spaces) -- count spaces
cross apply (values (replace(clean.fn, ' ','.'))) dotted(fn)
)
select original, cleaned =
case spaces
when 1 then parsename(prepped,1)+' '+parsename(prepped,2)
when 2 then parsename(prepped,2)+' '+parsename(prepped,1)+' '+parsename(prepped,3)
when 3 then parsename(prepped,2)+' '+parsename(prepped,1)+' '+parsename(prepped,3)+
' '+parsename(prepped,4)
end
from clean
<强>返回：
original cleaned
-------------------- ------------------
Malone,Susan M Susan M Malone
Conn,Chris G Chris G Conn
Van Pess,Wen B Wen B Pess Van
DESHPANDE, ANN W. ANN W DESHPANDE
Asif,LEE LEE Asif
CERVANTES MANDY MANDY CERVANTES
Bill, Dave Dave Bill
SMITH,ANN M ANN M SMITH
BHULLER, MATT MATT BHULLER
KIM (DAUM), GAIL GAIL KIM
John.Mills Mills John
或者，您可以使用正则表达式clr（mdq.regexreplace）。几年前注意我的post on SSC。