我试图找到一种方法来使用 rtweet 包从Twitter REST API执行对GET friendships/show的请求,以便分析两个用户之间的关系。但是,我无法使它工作(我确实找到lookup_friendships()
,但它没有做我想要的)。是否可以使用 rtweet 执行此操作,如果是,如何执行此操作?
答案 0 :(得分:1)
此功能已添加到rtweet,因此至少应该合理地访问" friendships / show" API通过lookup_friendships()
- 而奖励,它现在已经在CRAN上的版本0.6.0
中被接受了!
必需的输入是source
和target
(可以是屏幕名称或用户ID)。如果只向source
或target
提供了一个用户,则可以在其他参数中传递任意数量的用户 - 保存Twitter API速率限制。
fds <- lookup_friendships(
source = "realDonaldTrump",
target = c("DRUDGE_REPORT", "seanhannity", "HuffPost", "maddow", "cnn")
)
> fds
# A tibble: 60 x 4
relationship user variable value
<chr> <chr> <chr> <chr>
1 source DRUDGE_REPORT id 25073877
2 source DRUDGE_REPORT id_str 25073877
3 source DRUDGE_REPORT screen_name realDonaldTrump
4 source DRUDGE_REPORT following TRUE
5 source DRUDGE_REPORT followed_by FALSE
6 source DRUDGE_REPORT live_following FALSE
7 source DRUDGE_REPORT can_dm FALSE
8 target realDonaldTrump id 14669951
9 target realDonaldTrump id_str 14669951
10 target realDonaldTrump screen_name DRUDGE_REPORT
# ... with 50 more rows
>
还可以在source
和target
参数中指定多个用户。但是,如果两个参数的长度都大于1,则向量必须具有相等的长度。
## vector of multiple users
usrs <- c(
"realDonaldTrump", "DRUDGE_REPORT", "seanhannity", "HuffPost", "maddow", "cnn"
)
fds <- lookup_friendships(
source = usrs,
target = usrs
)
> fds
# A tibble: 72 x 4
relationship user variable value
<chr> <chr> <chr> <chr>
1 source realDonaldTrump id 25073877
2 source realDonaldTrump id_str 25073877
3 source realDonaldTrump screen_name realDonaldTrump
4 source realDonaldTrump following FALSE
5 source realDonaldTrump followed_by FALSE
6 source realDonaldTrump live_following FALSE
7 source realDonaldTrump can_dm TRUE
8 target realDonaldTrump id 25073877
9 target realDonaldTrump id_str 25073877
10 target realDonaldTrump screen_name realDonaldTrump
# ... with 62 more rows
还没有很多时间来测试它。如果您遇到问题,请尝试设置parse = FALSE
。您可以自己处理返回的数据,但这可能有助于避免内部解析中的错误。
fds <- lookup_friendships(
source = usrs,
target = usrs,
parse = FALSE
)
> str(fds, 3)
List of 6
$ realDonaldTrump:List of 1
..$ relationship:List of 2
.. ..$ source:List of 16
.. ..$ target:List of 7
$ DRUDGE_REPORT :List of 1
..$ relationship:List of 2
.. ..$ source:List of 16
.. ..$ target:List of 7
$ seanhannity :List of 1
..$ relationship:List of 2
.. ..$ source:List of 16
.. ..$ target:List of 7
$ HuffPost :List of 1
..$ relationship:List of 2
.. ..$ source:List of 16
.. ..$ target:List of 7
$ maddow :List of 1
..$ relationship:List of 2
.. ..$ source:List of 16
.. ..$ target:List of 7
$ cnn :List of 1
..$ relationship:List of 2
.. ..$ source:List of 16
.. ..$ target:List of 7
答案 1 :(得分:0)
您可以使用get_friends()
或get_followers()
功能。