Question

我一直在寻找有关如何在Mysql查询中在JSON对象中创建JSON数组的解决方案。需要你们任何人的帮助。

我在mysql中的源数据：

Table: parent
--------------------------------------
| id | firstname | lastname | rating |
--------------------------------------
|  1 | John      | Doe      | 9.3    |
|  2 | Marry     | Jane     | 8.5    |
|  3 | Paijo     | Masni    | 9.8    |
--------------------------------------

Table: children
------------------------------
| id |  idparent  | name     |
------------------------------
|  1 |  1         | John A   |
|  2 |  1         | John B   |
|  3 |  1         | John C   |
|  4 |  2         | Jane A   |
|  5 |  2         | Jane B   |
|  6 |  3         | Bang Jo  |
|  7 |  3         | Kak Jo   |
------------------------------

我的MySQL查询：

选择p.firstname，p.lastname，p.rating，c.name作为子项来自父p在p.id = c.idparent

上加入儿童c

Output:
-------------------------------------------------
| id | firstname | lastname | rating | children |
-------------------------------------------------
|  1 | John      | Doe      | 9.3    | John A   |
|  1 | John      | Doe      | 9.3    | John B   |
|  1 | John      | Doe      | 9.3    | John C   |
|  2 | Marry     | Jane     | 8.5    | Jane A   |
|  2 | Marry     | Jane     | 8.5    | Jane B   |
|  3 | Paijo     | Masni    | 9.8    | Bang Jo  |
|  3 | Paijo     | Masni    | 9.8    | Kak Jo   |
-------------------------------------------------

这是我想要的JSON格式输出：

var profile = [
    {
        "firstname": "John",
        "lastname": "Doe",
        "rating": 9.3,
        "children": [
            "John A",
            "John B",
            "John C"
        ],
        "id": 1
    },
    {
        "firstname": "Marry",
        "lastname": "Jane",
        "rating": 8.5,
        "children": [
            "Jane A",
            "Jane B"
        ],
        "id": 2
    },
    {
        "firstname": "Paijo",
        "lastname": "Masni",
        "rating": 9.8,
        "children": [
            "Bang Jo",
            "Kak Jo"
        ],
        "id": 3
    }
];

我从生成JSON中遇到的那个是关于孩子的：[]，我想要一个带双引号的数组＆＃34;＆＃34;以逗号分隔，＆＃39;＆＃39;在 - 的里面 []。

谢谢。

NB：我正在使用codeigniter进行编码。如果您以前在codeigniter上遇到过这种问题，我期待着与您分享。

Answer 1

$people = array();
$person = array();

$person['firstname'] = "John";
$person['lastname'] = "Doe";
$person['rating'] = 9.3;
$person['children'] = array('John A', 'John B', 'John C');
$person['id'] = 1;

$people[] = $person;
$person = array();

$person['firstname'] = "Marry";
$person['lastname'] = "Jane";
$person['rating'] = 8.5;
$person['children'] = array('JaneA', 'JaneB');
$person['id'] = 2;

$people[] = $person;

$profile = json_encode($people);

echo $profile;

提供以下输出：

[{"firstname":"John","lastname":"Doe","rating":9.3,"children":["John A","John B","John C"],"id":1},
{"firstname":"Marry","lastname":"Jane","rating":8.5,"children":["JaneA","JaneB"],"id":2}]

Answer 2

我正在使用NEIL的阵列结构

在codeigniter中，最后使用以下代码进行编码。

from core import settings

它将输出以下内容：

$this->output->set_content_type('application/json'); $this->output->set_output(json_encode($your_array));

在AJAX返回时，使用$ .parseJSON（数据）来获取所需的结果。

Answer 3

感谢所有人，感谢宝贵的回应。我刚刚得到了解决方案。

通过使用mysql中的任何可用函数搜索任何解决方案（我使用的是json_extract（）和group_concat（）），但它没有像我想要的那样提供最佳格式。

受上述答案的启发，我在Codeigniter中制作了这样的代码，完美无缺：

$parent   = array();
$children = array();
$profile  = array();

$parent_query = $this->db->query("select firstname, lastname, rating, id from parent")->result_array();

for($i = 0; $i < count($parent_query); $i++)
{
   $children_query = $this->db->query("select name from children where idparent = '$parent_query[$i]['id']'")->result_array();

   $parent[$i]['firstname'] = $parent_query[$i]['firstname'];
   $parent[$i]['lastname']  = $parent_query[$i]['lastname'];
   $parent[$i]['rating']    = $parent_query[$i]['rating'];

   for($j = 0; $j < count($children_query); $j++)
   {
      $children[] = $children_query[$j]['name'];
   }

   $parent[$i]['children']  = $children;
}

$profile = json_encode($parent);

给出的结果：

[  
   {  
      "firstname":"John",
      "lastname":"Doe",
      "rating":9.3,
      "children":[  
         "John A",
         "John B",
         "John C"
      ],
      "id":1
   },
   {  
      "firstname":"Marry",
      "lastname":"Jane",
      "rating":8.5,
      "children":[  
         "Jane A",
         "Jane B"
      ],
      "id":2
   },
   {  
      "firstname":"Paijo",
      "lastname":"Masni",
      "rating":9.8,
      "children":[  
         "Bang Jo",
         "Kak Jo"
      ],
      "id":3
   }
]

如何在json数组codeigniter中创建json数组

3 个答案: