Question

我一直试图找到搜索特定值并提取数据的最佳方法。我是新人，希望我的措辞正确。

    {"family": {
    "name": "Mary",
    "age": "32",
    "sex": "female",
    "kids": [
      {
        "name": "jim",
        "age": "10",
        "sex": "male",
        "dob_year": "2007",
        "ssn": "123-23-1234"
      },
      {
        "name": "jill",
        "age": "6",
        "sex": "female",
        "dob_year": "2011",
        "ssn": "123-23-1235"
      }]}}

如果我需要搜索包含“1234”的“ssn”并返回“名称”“jim”，那么最好的方法是什么呢？

Answer 1

您可以先迭代孩子并应用条件

import json
js = '''your json text data'''
j = json.loads(js)

for items in j['family']['kids']:
    if '1234' in items['ssn']:
        print(items['name'])

输出

'jim'

Answer 2

使用json包，如下所示

ans =     '{"family": {
    "name": "Mary",
    "age": "32",
    "sex": "female",
    "kids": [
      {
        "name": "jim",
        "age": "10",
        "sex": "male",
        "dob_year": "2007",
        "ssn": "123-23-1234"
      },
      {
        "name": "jill",
        "age": "6",
        "sex": "female",
        "dob_year": "2011",
        "ssn": "123-23-1235"
      }]}}'
temp = json.loads(ans)
for kid in  temp['family']['kids']:
     print kid['name'],kid['ssn']

希望这就是你要找的东西。

Answer 3

假设您将json文本加载到js变量中。 kn = next((sj['name'] for sj in js['family']['kids'] if ('1234' in sj['ssn'])), None)

如果找到标准，

kn将为您提供名称，否则将为无。当然，您可以将条件更改为变量。希望它有所帮助。

Answer 4

我更愿意提供处理这种情况的常用方法，基于python函数编程的直到方法，使用此方法，您可以找到您的目标（提供默认值）如果没有找到），你可以轻松地将你的过滤标准和候选人分开。

json_str = """
{"family": {
    "name": "Mary",
    "age": "32",
    "sex": "female",
    "kids": [
      {
        "name": "jim",
        "age": "10",
        "sex": "male",
        "dob_year": "2007",
        "ssn": "123-23-1234"
      },
      {
        "name": "jill",
        "age": "6",
        "sex": "female",
        "dob_year": "2011",
        "ssn": "123-23-1235"
      }]}}
"""

将数据加载到python dict对象

import json
data = json.loads(json_str)

现在到了这里：

def until(terminate, iterator, default=None):
    try:
        i = next(iterator)
        if terminate(i):
            return i
        return until(terminate, iterator, default)
    except StopIteration:
        return default


ssn_target = '1234'

target_kid = until(lambda kid: ssn_target in kid['ssn'], iter(data['family']['kids']))

if target_kid is not None:
    print(target_kid['name'])
else:
    print('Opps! not found')

请注意：

Python对可以进行多少次递归调用（通常约为1000）有一个相当小的限制，因此可迭代列表不应该太长。

Answer 5

实际上是关于从文件

中提取的问题

所以您在这里

import json

with open('data.json') as json_file:
    data = json.load(json_file)
    for kid in data['family']['kids']:
        if '1234' in kid['ssn']:
            print(kid['name'])

其他阅读：https://stackabuse.com/reading-and-writing-json-to-a-file-in-python/

从python中的json文件中提取数据

5 个答案: