我有一个关于套接字编程的简单问题。我已经完成了以下代码实现服务器和两个客户端,但突然间它在相互通信时停止。我不知道为什么会一直这样。
你能给我建议,提示或帮助吗? 谢谢你的时间。
# simple client
import socket
import sys
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = ""
port = 12345
buf = 100
s.connect((host, port))
i = 0
timestep = 0
while(1):
k = '01'#+str(timestep)
#1
s.send(k)
print 'sending message is', k
#2
v = s.recv(buf)
print v
if v == 'hold 01':
print 'timestep is', timestep#'send the previous message'
if timestep == 0:
timestep == 0
else:
timestep -= 1
else:
print 'read data'
FILE = open("datainfo1.txt", "r+")
msg = FILE.read()
FILE.close()
#3
while(1):
tmp, msg = msg[:buf], msg[buf:]
s.send(tmp)
print len(tmp)
if len(tmp) < buf:
print 'break'
break
# send file
i+=1
timestep+=1
print 'end'
s.close()
import socket, sys
# set up listening socket
lstn = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = ""
port = 12345
# bind lstn socket to this port
lstn.bind(("", port))
lstn.listen(5)
# initialize buffer size
buf = 100
# initialize concatenate string, v
v = ''
# initialize client socket list
cs = []
check = [0, 0]
# a fixed number of clients
nc = 1
count = 0
status = [0,0]
j = 0
step = [0,0]
for i in range(nc):
(clnt,ap) = lstn.accept()
clnt.setblocking(0)
cs.append(clnt)
file = open("output_analysis.txt","w+")
while (len(cs) > 0):
clnt = cs.pop(0)
cs.append(clnt)
try:
#1
k = clnt.recv(buf)
print "k=",k,"\n"#[:2]
if k == '01':
print "1st client connected", status[0]
file.write("1st\t")
if status[0] == 0:
v = 'hold 01'
check[0] = 1
elif status[0] == 1:
v = 'go 01'
# status[0] = 0
print v, "the message\n"
file.write(v)
file.write("\t")
#2
clnt.send(v)
if status[0] == 1:
FILE = open("client1.txt","w+")
print 'receive 01'
#3
while(1):
status[0] = 0
print '1st : receiving'
msg = clnt.recv(buf)
print len(msg)
if len(msg) < buf:
print 'break'
#FILE.close()
break
elif k == '02':
print "2nd client connected", status[0]
file.write("2nd\t")
if status[1] == 0:
v = 'hold 02'
check[1] = 1
elif status[1] == 1:
v = 'go 02'
# status[0] = 0
print v, "the message\n"
file.write(v)
file.write("\t")
#2
clnt.send(v)
if status[1] == 1:
FILE = open("client2.txt","w+")
print 'receive 02'
#3
while(1):
status[1] = 0
print '2nd : receiving'
msg = clnt.recv(buf)
print len(msg)
if len(msg) < buf:
print 'break'
#FILE.close()
break
if check[0] == 1:# and check[1] == 1:
print j, 'here\n'
j += 1
for i in range(2):
check[i] = 0
status[i] = 1 # which means, all clients are connected
print check, status
else:
print 'hello'
except: pass
file.close()
lstn.close()
答案 0 :(得分:3)
except: pass
你忽略了所有异常。这是一个坏主意,因为它不会让你知道什么时候出错。在合理调试代码之前,您需要删除except
处理程序。
答案 1 :(得分:2)
一个问题是您正在设置非阻止模式:
clnt.setblocking(0)
但永远不要检查发送或recv数据是否安全。事实证明,由于代码忽略了所有异常,因此在删除try时没有看到以下错误:
异常[Errno 10035]无法立即完成非阻塞套接字操作
删除setblocking
电话后,代码继续进行,但仍有问题。
描述您尝试解决的问题将有助于理解代码尝试执行的操作。