Question

在这里输入代码

<taskdef  name="groovy" classname="org.codehaus.groovy.ant.Groovy"/>                                                                      
     <groovy>            
    newFile("C://RxBen//exports//Control_Exception__c_Exportupdated.csv").withWriter {                                          
    new File("C://RxBen//exports//Control_Exception__c_Export.csv").splitEachLine(",(?=(?:[^\"]*\"[^\"]*\")*[^\"]*\$)") { ID, Don_t_Work__c,Forwarding_fax_number__c, No_Go__c  ->
     it.println "${ID},${Forwarding_fax_number__c}AAA,${s}"                                                           
     }                                             
    }                             
    </groovy>

Answer 1

您可以在参数为2的列中使用字符串上的子字符串，这将从目标字符串中的第三个字符到字符串末尾的所有字符。

示例：

def s = "AATestString"
def newString = s.substring(2)
assert newString == "TestString"

Answer 2

<强>更新
试试这个代码：Ozsaffer接近......

@Grab('com.xlson.groovycsv:groovycsv:1.1')
import static com.xlson.groovycsv.CsvParser.parseCsv 

df = new FileReader('filename.csv') 

def data = parseCsv(df, readFirstLine: false) 

for (def row : data){

println row.values[0].substring(2)  //row.values[0] means first column 
}

如何使用groovy修剪csv中列的前两个字符

2 个答案: