我不明白为什么getAges
被跳过。
#include <iostream>
#include <cctype>
using namespace std;
int getAges(int age, const int SIZE);
char getChoice();
void displayInOrder(int numbers[], const int SIZE, char choice);
void displayInReverse(int numbers[], const int SIZE, char choice);
int main()
{
const int SIZE = 5;
int numbers[SIZE] = { 1, 2 ,3 ,4, 5 };
char answer;
int age;
char choice;
if (toupper(choice) == 'O')
{
displayInOrder(numbers, SIZE, choice);
}
else if (toupper(choice) == 'R')
{
displayInReverse(numbers, SIZE, choice);
}
else
{
cout << "Invalid entry! - Must be O or R\n\n";
}
if (toupper(answer) == 'Y')
{
system("cls");
age = getAges(age, SIZE);
choice = getChoice();
displayInOrder(numbers, SIZE, choice);
displayInReverse(numbers, SIZE, choice);
cout << "Run program again (Y or N)? ";
cin >> answer;
break;
}
else if (toupper(answer) == 'N')
{
return 0;
}
return 0;
}
int getAges(int age, const int SIZE)
{
cout << "Enter " << SIZE << " ages: \n\n";
cin >> age;
cout << endl;
cin >> age;
cout << endl;
cin >> age;
cout << endl;
cin >> age;
cout << endl;
cin >> age;
cout << endl;
return age;
}
char getChoice()
{
char choice;
cout << "How do you want to see the ages displayed? \n\n Enter O for In Order, or R for In Reverse.\n\n";
cin >> choice;
return choice;
}
void displayInOrder(int numbers[], const int SIZE, char answer)
{
cout << "Here are the ages in order: \n\n";
for (int i = 0; i < SIZE; i++)
{
cout << numbers[i] << endl;
}
}
void displayInReverse(int numbers[], const int SIZE, char answer)
{
cout << "Here are the ages in reverse order: \n\n";
for (int i = SIZE - 1; i >= 0; i--)
{
cout << numbers[i] << endl;
}
}
答案 0 :(得分:1)
在OP将标题更新为关于“while循环和中断语句”的原始问题之前,我开始研究这个问题。然而,当我遇到这个问题时,OP最初删除了while循环。我正在查看提供的函数,以了解OP正在尝试做什么,这就是我想出的。
首先:
while loops
正是您想要的,但在这种情况下,您需要特定类型的while loop
,do-while loop
。下一步:如果您知道如何正确构建
break
,则无需do-while loop
语句。最后:我通过更改或删除不必要的
functions
,parameter(s)
&amp;来对OP的现有return type(s)
做了一些修改。code duplication
。我删除了不再需要的function
。我更改了消息的output formatting
以显示干净的程序。我还删除了在全局范围内使用using namespace std;
的不良做法。
我这样做是为了向OP演示如何在不需要break语句的情况下构建while循环,并且它们最初是在正确的轨道上,但需要一些帮助才能继续前进。
以下是我认为OP的目标是工作程序的源代码。
#include <iostream>
#include <cctype>
void getAge( int& age );
void displayInOrder( int numbers[], const int SIZE);
void displayInReverse( int numbers[], const int SIZE );
int main() {
const int SIZE = 5;
int numbers[SIZE] = { 0 };
char answer = '\0';
int age = 0;
char choice = '\0';
std::cout << "========================================================================\n"
<< "This program will have the user enter in "
<< SIZE
<< " Ages. \nThen ask the user in which order to display the list of ages.\n"
<< "Finally the program will ask the user if they want to continue or not.\n"
<< "========================================================================\n\n";
do {
for ( int i = 0; i < SIZE; i++ ) {
getAge( age );
numbers[i] = age;
}
std::cout << "\nPlease enter 'O' for ordered or 'R' for reversed list.\n";
std::cin >> choice;
if ( toupper( choice ) == 'O' ) {
displayInOrder( numbers, SIZE );
}
if ( toupper( choice ) == 'R' ) {
displayInReverse( numbers, SIZE );
}
std::cout << "\nDo you want to run program again (Y/N)?";
std::cin >> answer;
} while ( toupper( answer ) == 'Y' );
return 0;
}
void getAge( int& age ) {
int temp;
std::cout << "Enter an age: \n";
std::cin >> temp;
age = temp;
}
void displayInOrder( int numbers[], const int SIZE ) {
std::cout << "\nHere are the ages in order: \n";
for ( int i = 0; i < SIZE; i++ ) {
std::cout << numbers[i] << std::endl;
}
}
void displayInReverse( int numbers[], const int SIZE ) {
std::cout << "\nHere are the ages in reverse order: \n";
for ( int i = SIZE - 1; i >= 0; i-- ) {
std::cout << numbers[i] << std::endl;
}
}