Question

希望选择2中的代码搜索从选项1创建的单词中的字母。我似乎无法找到解决方案。

if choice==1:
    print ("Enter a Word")
    minput= input()

    wordList= list (minput)
    print (wordList)

    mainMenu()

if choice==2:
    letter=['a,b,c,d, e, f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z']
    counter=0
    searchletter=input('Enter letter to search\t')

    while counter<len(letter) and searchletter!=letter[counter]:
        counter+=1
    if counter <len(letter):
        print(searchletter,'found')
    else:
        print(searchletter, ' Not found')
        mainMenu()

Answer 1

您的问题出在while循环中。目前，在搜索时，您的循环将退出第一个不是您的搜索字母的字符。相反，你可以简单地使用

print("found" if searchletter in word else "not found")

并将您的单词的变量名称放在word。

中

>>> word = "testme"
>>> searchletter = "t"
>>> print("found" if searchletter in word else "not found")
found
>>> searchletter = "f"
>>> print("found" if searchletter in word else "not found")
not found

如何在用户生成的单词中搜索字母

1 个答案: