将MySql表数据选择为数组

时间:2011-01-18 21:36:19

标签: php mysql arrays metadata

我尝试从mysql中捕获数据,将它们全部放入数组中。 假设:

    users table
    -----------------------
    id| name | code 
    ----------------------
    1| gorge | 2132
    2| flix | ksd02
    3| jasmen | skaod2

    $sql = mysql_query("select id, name, code from users");
    $userinfo = array()
    while($row_user = mysql_fetch_array($sql)){
    $userinfo = $row_user[name] 
    }
-------------------------
foreach($userinfo as $usinfo){
echo $usinfo."<br/>";
}

这是问题我只能插入用户名但不能插入代码&amp; userinfo数组中的id请帮我在同一个数组中插入所有数据。

[P.S]请不要面向对象。

4 个答案:

答案 0 :(得分:31)

$sql = mysql_query("select id, name, code from users");
$userinfo = array();

while ($row_user = mysql_fetch_assoc($sql))
    $userinfo[] = $row_user;

这将为您提供$userinfo作为具有以下结构的数组:

[
    [id => 1, name => 'gorge', code => '2123'],
    [id => 2, name => 'flix', code => 'ksd02'],
    [id => 3, name => 'jasmen', code => 'skaod2']
]

如果要输出数据:

foreach ($userinfo as $user) {
    echo "Id: {$user[id]}<br />"
       . "Name: {$user[name]}<br />"
       . "Code: {$user[code]}<br /><br />";
}

答案 1 :(得分:4)

while($row_user = mysql_fetch_assoc($sql)){
   $userinfo[] = $row_user;
}

foreach($userinfo as $usrinfo){
   echo "Id: ".$usrinfo['id']."<br />";
   echo "Name: ".$usrinfo['name']."<br />";
   echo "Code: ".$usrinfo['code']."<br />";
}

答案 2 :(得分:4)

我发现了这段代码,我节省了一天的时间:

<?php
$sql=mysql_query("select * from table1");

/*every time it fetches the row, adds it to array...*/
while($r[]=mysql_fetch_array($sql));

echo "<pre>";
// Prints $r as array 
print_r ($r);
echo "</pre>";
?>

答案 3 :(得分:-4)

   while($row_user = mysql_fetch_array($sql)){
    $row_id = $row_user ["id"];
        $row_author = $row_user ["author"];
        $row_code = $row_user ["code"];
       $userinfo[] = array("id"=> $row_id , "author"=> $row_author, "code"=> $row_code);
    }
foreach ($userinfo as $user) {
    echo "Id: {$user[id]}\n"
       . "Name: {$user[name]}\n"
       . "Code: {$user[code]}\n\n";
}