Question

我正在创建一个本体，我想从dbpedia添加数据。例如，我想添加有关瑞士的数据。这就是我在做的事。

g = Graph()
sparql = SPARQLWrapper("http://dbpedia.org/sparql")
query = """
    PREFIX dbo:  <http://dbpedia.org/ontology/>
    PREFIX dbpedia: <http://dbpedia.org/resource/>
    PREFIX dbp: <http://dbpedia.org/property/>
    PREFIX geo: <http://www.w3.org/2003/01/geo/wgs84_pos#>
    SELECT DISTINCT  ?s ?pop ?code
    WHERE{ 
       ?s rdf:type  dbo:PopulatedPlace.
       ?s dbp:iso3166code ?code.
       ?s dbo:populationTotal ?pop.
       FILTER (?s = dbpedia:Switzerland)
    }
"""
sparql.setQuery(query)
sparql.setReturnFormat(JSON)
results = sparql.query().convert()

然后我将我提取的信息添加到我的图表中

for result in results["results"]["bindings"]:
    N = int(result["pop"]["value"])
totPopulation   = Literal(N)
g.add(( cName, RDF.type, dbo.Country))
g.add(( cName, dbo.populationTotal, totPopulation ))
g.add(( cName, dbp.iso3166code, Literal(str(result["code"]["value"])) ))

有没有更简单的方法呢？

Answer 1

使用SPARQL CONSTRUCT查询可能会更容易，因为此查询类型返回一组本机RDF三元组：

from rdflib import Graph
from SPARQLWrapper import SPARQLWrapper, RDF

# create empty graph
g = Graph() 

# execute SPARQL CONSTRUCT query to get a set of RDF triples
sparql = SPARQLWrapper("http://dbpedia.org/sparql")
sparql.addDefaultGraph("http://dbpedia.org")
query = """
    PREFIX dbpedia: <http://dbpedia.org/resource/> 
    CONSTRUCT { 
     ?s rdf:type dbo:PopulatedPlace. 
     ?s dbp:iso3166code ?code. 
     ?s dbo:populationTotal ?pop. 
    } WHERE{ 
     ?s rdf:type dbo:PopulatedPlace. 
     ?s dbp:iso3166code ?code. 
     ?s dbo:populationTotal ?pop. 
     FILTER (?s = dbpedia:Switzerland) 
    }
"""
sparql.setQuery(query)
try : 
    sparql.setReturnFormat(RDF)
    results = sparql.query()
    triples = results.convert() # this converts directly to an RDFlib Graph object
except: 
    print "query failed"


# add triples to graph
g += triples

Python：如何使用rdflib将Dbpedia中的信息添加到我的图形中？

1 个答案: