Question

我正在创建一个自定义图层，其权重需要在激活之前按元素乘以。当输出和输入是相同的形状时，我可以使它工作。当我将第一个数组作为输入并将第二个数组作为输出时，会出现问题。 tensorflow.multiply支持广播，但是当我尝试在Layer.call（x，self.kernel）中使用它时将x乘以self.kernel变量它抱怨它们是不同的形状说：

ValueError: Dimensions must be equal, but are 4 and 3 for 'my_layer_1/Mul' (op: 'Mul') with input shapes: [?,4], [4,3].

这是我的代码：

from keras import backend as K
from keras.engine.topology import Layer
import tensorflow as tf
from keras.models import Sequential
import numpy as np

class MyLayer(Layer):

    def __init__(self, output_dims, **kwargs):
        self.output_dims = output_dims

        super(MyLayer, self).__init__(**kwargs)

    def build(self, input_shape):
        # Create a trainable weight variable for this layer.
        self.kernel = self.add_weight(name='kernel',
                                      shape=self.output_dims,
                                      initializer='ones',
                                      trainable=True)


        super(MyLayer, self).build(input_shape)  # Be sure to call this somewhere!

    def call(self, x):
        #multiply wont work here?
        return K.tf.multiply(x, self.kernel)

    def compute_output_shape(self, input_shape):
        return (self.output_dims)

mInput = np.array([[1,2,3,4]])
inShape = (4,)
net = Sequential()
outShape = (4,3)
l1 = MyLayer(outShape, input_shape= inShape)
net.add(l1)
net.compile(loss='mean_absolute_error', optimizer='adam', metrics=['accuracy'])
p = net.predict(x=mInput, batch_size=1)
print(p)

编辑：给定输入形状（4，）和输出形状（4,3），权重矩阵应与输出形状相同，并用1初始化。所以在上面的代码中输入是[1,2,3,4]，权重矩阵应该是[[1,1,1,1]，[1,1,1,1]，[1,1,1] ，1]]和输出应该像[[1,2,3,4]，[1,2,3,4]，[1,2,3,4]]

Answer 1

在相乘之前，您需要重复元素以增加形状。您可以使用K.repeat_elements。（import keras.backend as K）

class MyLayer(Layer):

    #there are some difficulties for different types of shapes   
    #let's use a 'repeat_count' instead, increasing only one dimension
    def __init__(self, repeat_count,**kwargs):
        self.repeat_count = repeat_count
        super(MyLayer, self).__init__(**kwargs)

    def build(self, input_shape):

        #first, let's get the output_shape
        output_shape = self.compute_output_shape(input_shape)
        weight_shape = (1,) + output_shape[1:] #replace the batch size by 1


        self.kernel = self.add_weight(name='kernel',
                                      shape=weight_shape,
                                      initializer='ones',
                                      trainable=True)


        super(MyLayer, self).build(input_shape)  # Be sure to call this somewhere!

    #here, we need to repeat the elements before multiplying
    def call(self, x):

        if self.repeat_count > 1:

             #we add the extra dimension:
             x = K.expand_dims(x, axis=1)

             #we replicate the elements
             x = K.repeat_elements(x, rep=self.repeat_count, axis=1)


        #multiply
        return x * self.kernel


    #make sure we comput the ouptut shape according to what we did in "call"
    def compute_output_shape(self, input_shape):

        if self.repeat_count > 1:
            return (input_shape[0],self.repeat_count) + input_shape[1:]
        else:
            return input_shape

Answer 2

这是另一个基于DanielMöller答案的解决方案，但是使用tf.multiply就像原始代码一样。

class MyLayer(Layer):

    def __init__(self, output_dim, **kwargs):
        self.output_dim = output_dim

        super(MyLayer, self).__init__(**kwargs)

    def build(self, input_shape):
        # Create a trainable weight variable for this layer.
        output_shape = self.compute_output_shape(input_shape)
        self.kernel = self.add_weight(name='kernel',
                                      shape=(1,) + output_shape[1:],
                                      initializer='ones',
                                      trainable=True)


        super(MyLayer, self).build(input_shape)  # Be sure to call this somewhere!

    def call(self, x):

        return K.tf.multiply(x, self.kernel)

    def compute_output_shape(self, input_shape):
        return (input_shape[0],self.output_dim)+input_shape[1:]

在keras自定义层中使用广播进行元素乘法

2 个答案: