使用PHP

Question

我正在使用Codeigniter来获取行。请仔细阅读以下代码。

//Model

public function selectData() {
    $query = $this->db->query('SELECT * FROM tbl_favourites WHERE favourites_status = 1');
    $count = $query->num_rows();

    if($count > 0)
        return $result = $query->result_array();
    else
        return 0;
}

//Controller

$all_favourites = $this->select->selectData();

if(!empty($all_favourites)) {
    foreach($all_favourites as $favourites)
        echo json_encode($favourites);
}

从上面的代码中，输出是

{"favourite_online_id":"3","favourite_online_url":"ddd","favourite_online_status":"0"}
{"favourite_online_id":"2","favourite_online_url":"http:\/\/www.google.com","favourite_online_status":"0"}

但我希望输出格式正确以满足android JSON。

所需的输出是，

[
  {
    "favourite_online_id": "3",
    "favourite_online_url": "ddd",
    "favourite_online_status": "0"
  },
  {
    "favourite_online_id": "2",
    "favourite_online_url": "http://www.google.com",
    "favourite_online_status": "0"
  }
]

Answer 1

而不是使用

if(!empty($all_favourites)) {
    foreach($all_favourites as $favourites)
        echo json_encode($favourites);
}

直接使用

if(!empty($all_favourites)) {

        echo json_encode($all_favourites );
}

Answer 2

你可以双向进行

第一路

if(!empty($all_favourites)) {
  echo json_encode($all_favourites);
}

第二路

如果你想在那个对象中添加一些内容，那么

$favouriteArray=[];
if(!empty($all_favourites)) {
    foreach($all_favourites as $favourites){
      array_push($favouriteArray, $favourites);
    }
}
echo json_encode($favouriteArray);

Answer 3

我认为你可以修改你的功能

public function selectData() {
    $query = $this->db->query('SELECT * FROM tbl_favourites WHERE favourites_status = 1');
    $count = $query->num_rows();

    if($count > 0)
        return $result = $query->result_array();
    else
        return array();
}

//Controller

$all_favourites = $this->select->selectData();

// if(!empty($all_favourites)) {
//    foreach($all_favourites as $favourites)
//        echo json_encode($favourites);
// }
echo json_encode($all_favourites);