我已经在这里工作了几天,几乎把头发拉了出来。
我正在尝试从FOREACH循环输出JSON,以便我可以使用它来模拟每日课程表。我已经有了大部分的方式,事情继续破裂或出乎意料。
以下代码产生了这个:
{
"DAY": "TUESDAY",
"TIME": {
"530": {
"CLASSES": [
{
"CLASS": {
"INSTRUCTOR": "DANA",
"CLASS_LEVEL": "JUNIOR",
"MAX_STUDENTS": "8"
}
},
{
"CLASS": {
"STUDENTS": [
{
"STUDENT": [
{
"FIRST NAME": "Alexandra",
"LAST NAME": "",
"DATE OF BIRTH": ""
}
]
}
]
}
},
{
"CLASS": {
"STUDENTS": [
{
"STUDENT": [
{
"FIRST NAME": "Leivi",
"LAST NAME": "",
"DATE OF BIRTH": ""
}
]
}
]
}
},
{
"CLASS": {
"STUDENTS": [
{
"STUDENT": [
{
"FIRST NAME": "Traivon",
"LAST NAME": "",
"DATE OF BIRTH": ""
}
]
}
]
}
},
{
"CLASS": {
"STUDENTS": [
{
"STUDENT": [
{
"FIRST NAME": "Keira",
"LAST NAME": "",
"DATE OF BIRTH": ""
}
]
}
]
}
},
{
"CLASS": {
"STUDENTS": [
{
"STUDENT": [
{
"FIRST NAME": "Madison",
"LAST NAME": "",
"DATE OF BIRTH": ""
}
]
}
]
}
},
但是,正如您所看到的,我希望“学生”嵌套在“CLASS”下面。我究竟做错了什么?我无法理解我的生活。我开始讨厌多维数组。 : - @
function dailySchedule() {
global $conn;
$sql = 'SET DATEFIRST 1
SELECT [DAY].[DAY] AS [DAY], CLASS.CLASSTIME AS CLASSTIME, CLASSLEVEL.CLASSLEVEL AS CLASSLEVEL, CLASS.MAXSTUDENT AS MAXSTUDENT,
INSTRUCTOR.FIRSTNAME AS INSTRUCTOR, STUDENT.FIRSTNAME AS STUDENTFIRST, STUDENT.SURNAME AS STUDENTLAST, STUDENT.DOB AS STUDENTDOB
FROM STUDENT JOIN BOOKING ON STUDENT.ID = BOOKING.STUDENTID JOIN CLASS ON CLASS.ID = BOOKING.CLASSID JOIN CLASSLEVEL ON
CLASS.CLASSLEVELID = CLASSLEVEL.ID JOIN [DAY] ON CLASS.CLASSDAY = [DAY].ID JOIN INSTRUCTOR ON CLASS.INSTRUCTORID = INSTRUCTOR.ID
WHERE [DAY].ID = (DATEPART(dw, GETUTCDATE() AT TIME ZONE \'AUS Eastern Standard Time\'))
ORDER BY CLASS.CLASSTIME ASC, INSTRUCTOR.FIRSTNAME ASC, CLASSLEVEL.CLASSLEVEL ASC';
$studentDetails =
$sqlEx = $conn->query($sql);
$schedule = array();
foreach($sqlEx as $rows) {
if(!isset($day) || $day !== $rows['DAY']) {
$day = $rows['DAY'];
$schedule = array('DAY' => $day) + $schedule;
}
if(!isset($time) || $time !== $rows['CLASSTIME']) {
$time = $rows['CLASSTIME'];
}
if(!isset($instructor) || $instructor !== $rows['INSTRUCTOR']) {
$instructor = $rows['INSTRUCTOR'];
$schedule['TIME'][$time]['CLASSES'][]['CLASS'] = [
'INSTRUCTOR' => $instructor,
'CLASS_LEVEL' => $rows['CLASSLEVEL'],
'MAX_STUDENTS' => $rows['MAXSTUDENT'],
];
}
//if($instructor == $rows['INSTRUCTOR']){
$schedule['TIME'][$time]['CLASSES'][]['CLASS']['STUDENTS'][]['STUDENT'][] = [
'FIRST NAME' => $rows['STUDENTFIRST'],
'LAST NAME' => $rows['STUDENTLAST'],
'DATE OF BIRTH' => $rows['STUDENTDOB']
];
//}
}
echo json_encode($schedule, JSON_PRETTY_PRINT);
}
先谢谢大家。
答案 0 :(得分:-1)
我不确定这是你想要的,但我最喜欢的方法是使用不同的方法:
$schedule = array();
foreach($sqlEx as $rows) {
$Day = $rows["DAY"];
$ClassTime = $rows["CLASSTIME"];
$ClassLevel = $rows["CLASSLEVEL"];
$MaxStudents = $rows["MAXSTUDENTS"];
$Instructor = $rows["INSTRUCTOR"];
$StudentFirst = $rows["STUDENTFIRST"];
$StudentLast = $rows["STUDENTLAST"];
$StudentDOB = $rows["STUDENTDOB"];
$schedule[$Day][$ClassTime]["CLASS"] = array("INSTRUCTOR" => $Instructor,"CLASS_LEVEL" =>$ClassLevel,"MAX_SUTENTS" => $MaxStudents);
$schedule[$Day][$ClassTime]["STUDENT"] = array("FIRSTNAME" => $StudentFirst ,"LASTNAME" => $StudentLast, "DATE OF BIRTH" => $StudentDOB);
}
echo json_encode($schedule, JSON_PRETTY_PRINT);