Question

var rock = rock;
var paper= paper;
var snip = snip;

var playerOneName= prompt("what is your name");
playerOne = choice();
var playerTwoName = prompt("what is your name");
playerTwo=choice();


function choice(pick){
	prompt("rock paper or snip");
}
if(playerOne === rock && playerTwo === snip){
    alert(playerOneName + " " + "Wins");
}else if(playerOne === paper && playerTwo === rock){
    alert(playerOneName + " " + "Wins");
}else if(playerOne === snip && playerTwo === paper){
    alert(playerOneName + " " + "Wins");
}else if(playerTwo === rock && playerOne === snip){
   alert(playerTwoName + " " + "Wins");
}else if(playerTwo === paper && playerOne === rock){
    alert(playerTwoName + " " + "Wins");
}else if(playerTwo === snip && playerOne === paper){
   alert(playerTwoName + " " + "Wins");
}else if(playerOne === playerTwo){
	alert("it's a tie try again");
}

<!doctype html>
<!DOCTYPE html>
<html>
<head>
	<title></title>
	<script src="rps.js"></script>
</head>
<body>

<ul>
	<li>Rock</li>
	<li>Paper</li>
	<li>Snip</li>
</ul>
</body>
</html>

大家好，我带着一个非常新的问题回来了。出于某种原因，当我为这个摇滚剪刀游戏运行我的代码时...它经常告诉我玩家赢了。我发现的问题是它始终选择if语句而不是else if。如果有人可以提供帮助那就太棒了！再次感谢你的时间。这也是我学习javascript的第一周......有点可悲的是，很多人都会对我的问题进行投票...这就是为什么大多数人都不敢问问题的原因... < / p>

Answer 1

您需要return来自window.prompt的输入值。即

function choice(pick){ var answer = prompt("rock paper or snip"); return answer; }

这样您就可以获得用户在窗口提示中输入的内容。在某些情况下，您可能需要检查null值。更多阅读at Mozilla Docs

Answer 2

尝试使用此更正并验证的JavaScript代码 -

#include <iostream>
#include <stdio.h>
#include <stdint.h>
/* run this program using the console pauser or add your own getch, system("pause") or input loop */


class FooBar{
public:
        typedef void(FooBar::*OnDio)(void);

    void OnDio0Irq( void ){
        printf("dio0\n");
    };
    void OnDio1Irq( void ){
        printf("dio1\n");
    };
    FooBar(){
        OnDio  dioArray[] = {&OnDio0Irq, &OnDio1Irq};

    };

    OnDio  *dioArray[2];
private:

};

int main(int argc, char* argv[]){
        typedef void(FooBar::*OnDio)(void);
        void (FooBar::*foo)(void);
    OnDio *myPtr;
    FooBar *fb = new FooBar();

    myPtr = *(&fb->dioArray[0]);
    foo = (OnDio &)(myPtr[0]);
    (foo)();//me need call fb->dioArray[0]()
    (*myPtr)(); // ?
 }

更正 -

var rock = rock; var paper= paper; var snip = snip; var playerOneName= prompt("what is your name"); playerOne = choice(); var playerTwoName = prompt("what is your name"); playerTwo=choice(); alert('Player 1 Chose - '+ playerOne + 'Player 2 Chose - '+playerTwo); function choice(pick){ return(prompt("rock paper or snip")); //return the prompt value } if(playerOne === 'rock' && playerTwo === 'snip'){ alert(playerOneName + ' ' + 'Wins'); }else if(playerOne === 'paper' && playerTwo === 'rock'){ alert(playerOneName + ' ' + 'Wins'); }else if(playerOne === 'snip' && playerTwo === 'paper'){ alert(playerOneName + ' ' + 'Wins'); }else if(playerTwo === 'rock' && playerOne === 'snip'){ alert(playerTwoName + ' ' + 'Wins'); }else if(playerTwo === 'paper' && playerOne === 'rock'){ alert(playerTwoName + ' ' + 'Wins'); }else if(playerTwo === 'snip' && playerOne === 'paper'){ alert(playerTwoName + ' ' + 'Wins'); }else if(playerOne === playerTwo){ alert('its a tie try again'); }函数中的返回值。提示具有在函数中接收和返回的返回值。
提醒并检查值以进行调试。总是尝试这一点来了解代码中发生的事情。

Javascript石头剪刀项目

2 个答案: