Question

我需要在codeigniter中创建一个查询，如下所示：

SELECT COUNT(*) AS `numrows` FROM `smslog_tbl` WHERE (lower(ResponseStatus) = 'submitted' OR lower(ResponseStatus) = 'inqueue') AND `SMSUsageID` = '1'

所以我在模型中创建了一个函数：

function submittedSMSCount($smsUsageID) {        
    $this->db->where('lower(ResponseStatus)', 'submitted');
    $this->db->or_where('lower(ResponseStatus)', 'inqueue');
    $this->db->where('SMSUsageID', $smsUsageID);
    return $this->db->count_all_results('smslog_tbl');
}

但此函数会生成如下查询：

SELECT COUNT(*) AS `numrows` FROM `smslog_tbl` WHERE lower(ResponseStatus) = 'submitted'OR lower(ResponseStatus) = 'inqueue' AND `SMSUsageID` = '1'

由于条件的原因，这两个查询会产生不同的结果。我需要将 OR 条件分组以获得正确的结果。如何使用codeigniter

执行此操作

Answer 1

function submittedSMSCount($smsUsageID) {       

$this->db->where(
       "(lower(ResponseStatus) = 'submitted' OR lower(ResponseStatus) = 'inqueue')", 
       NULL, 
       FALSE
 );  
$this->db->where('SMSUsageID', $smsUsageID);

return $this->db->count_all_results('smslog_tbl');

}

$this->db->where()接受可选的第三个参数。如果你设置它为FALSE，CodeIgniter不会试图保护你的领域或表带反叛的名字。

参考： https://www.codeigniter.com/userguide3/database/query_builder.html#looking-for-specific-data

Answer 2

function submittedSMSCount($smsUsageID) { 
    $where = "(lower(ResponseStatus) = 'submitted' OR lower(ResponseStatus) = 'inqueue')";
    $this->db->where($where);
    $this->db->where('SMSUsageID', $smsUsageID);
    return $this->db->count_all_results('smslog_tbl');
}

Answer 3

将组与查询构建器一起使用

function submittedSMSCount($smsUsageID) {        
    $this->db->select('COUNT(*) AS numrows')
    ->group_start()
    ->where('lower(ResponseStatus)', 'submitted')
    ->or_where('lower(ResponseStatus)','inqueue')
    ->group_end()
    ->where('SMSUsageID', $smsUsageID);
    return $this->db->get('smslog_tbl');
}

输出

SELECT COUNT（*）AS numrows FROM smslog_tbl WHERE（lower（ResponseStatus）=＆＃39;提交＆＃39;或更低（ResponseStatus）=＆＃39; inqueue＆＃39;）AND {{1 }} =＆＃39; 1＆＃39;

在codeigniter中

3 个答案: