Question

我想测试捕获格式异常，但如果我尝试输入任何单词，程序会崩溃。如何让我的程序捕获异常而不会崩溃？

string words;
int[] number;
int i = 0;

while (true)
{
    Console.WriteLine("How many numbers would you like to enter? ");
    words = Console.ReadLine();

    if (isInteger(words))
    {
        number = new int[Convert.ToInt32(words)];
        Console.WriteLine("Please enter your numbers: ");

        for (i = 0; i < number.Length; ++i)
        {
            number[i] = Convert.ToInt32(Console.ReadLine());
            isInteger(words);
        }
    }
}

isInteger方法：

private static bool isInteger(string words)
{
    try
    {
         return true;
    }
    catch (FormatException)
    {
        return false;
    }
}

Answer 1

如果要捕获对Convert Convert.ToInt32(words)或Convert.ToInt32(Console.ReadLine())的调用引发的异常，则需要将它们包装在try catch块中。任何catch只处理前一次try中发生的异常。所以，例如

try
{
  number = new int[Convert.ToInt32(words);
}
catch (FormatException ex)
{
  // Do something here ex is needed if you want to look at the exception
}

或者你可以将它全部包装在一个试试中

try
{
  number = new int[Convert.ToInt32(words);
  Console.WriteLine("Please enter your numbers: ");

  for (i = 0; i < number.Length; ++i)
  {
    number[i] = Convert.ToInt32(Console.ReadLine());
    isInteger(words);
  }
}
catch (FormatException ex)
{
  // Do something here ex is needed if you want to look at the exception
}

isInteger将永远不会有异常处理，因为它所做的只是返回true，它永远不会被处理。如果要处理函数中的异常，则该函数必须进行除catch或在catch块中调用的调用。

格式异常 - 捕获和尝试

1 个答案: