我正在Python中创建一个实用程序,它在一个单独的线程上从启动时的文件中读取数据,以便可以加载其余的GUI组件。数据存储在list
中,然后附加到组合框中。如何锁定list
,以便其他方法无法在def read_employees(self, read_file):
方法使用的同时调用列表。
这是我能想到的最好的尝试。
#left out imports
class MyDialog(wx.Frame):
def __init__(self, parent, title):
self.no_resize = wx.DEFAULT_FRAME_STYLE & ~ (wx.RESIZE_BORDER | wx.MAXIMIZE_BOX)
wx.Frame.__init__(self, parent, title=title, size=(500, 450),style = self.no_resize)
self.lock = threading.RLock()
self.empList = []
def read_employees(self, read_file):
with open(read_file) as f_obj:
employees = json.load(f_obj)
with self.lock:
self.empList = [empEmail for empEmail in employees.keys()]
wx.CallAfter(self.emp_selection.Append, self.empList)
def start_read_thread(self):
filename = 'employee.json'
with concurrent.futures.ThreadPoolExecutor(max_workers=1) as executor:
executor.submit(self.read_employees, filename)
app = wx.App(False)
frame = MyDialog(None, "Crystal Rose")
app.MainLoop()
这里使用的是RLock
吗?
答案 0 :(得分:1)
我不知道你在应用中发生了什么,但我建议你看一下wx.CallAfter函数。它是线程安全的,可用于发送消息或发布事件。
import wx
from wx.lib.pubsub import Publisher
import json
from threading import Thread
def update_employee_list(read_file):
with open(read_file) as f_obj:
employee_list = json.load(f_obj) # this line should release the GIL so it continues other threads
# next line sends a thread-safe message to the main event thread
wx.CallAfter(Publisher().sendMesage, 'updateEmployeeList', employee_list)
class MyDialog(wx.Frame):
def __init__(self, parent, title):
self.no_resize = wx.DEFAULT_FRAME_STYLE & ~ (wx.RESIZE_BORDER | wx.MAXIMIZE_BOX)
wx.Frame.__init__(self, parent, title=title, size=(500, 450),style = self.no_resize)
self.empList = []
# subscribe our function to be called when 'updateEmployeeList' messages are received
Publisher().subscribe(self.updateDisplay, 'updateEmployeeList')
def updateDisplay(self, employee_list):
# this assignment should be atomic and thread-safe
self.empList = employee_list
# wxPython GUI runs in a single thread, so this is a blocking call
# if you have many many list items, you may want to modify this method
# to add one employee at a time to the list to keep it non-blocking.
self.emp_selection.Append(employee_list)
def start_read_thread(self):
filename = 'employee.json'
t = Thread(target= update_employee_list, args=(filename, ))
t.start() # this starts the thread and immediately continues this thread's execution
更新
使用with ThreadPoolExecutor
块,因为代码等同于:
executor = ThreadPoolExecutor(max_workers=1)
executor.submit(worker_func, args)
executor.shutdown(wait=True) # <--- wait=True causes Executor to block until all threads complete
你仍然可以使用ThreadPoolExecutor,如下所示,没有with块。因为你只是:
executor = ThreadPoolExecutor(max_workers=1)
executor.submit(worker_func, args)
executor.shutdown(wait=False) # <--- threads will still complete, but execution of this thread continues immediately
有关并发期货和执行人的更多信息,see here for documention。