Question

如何获得此脚本的良好输出：来源JSON：https://ufile.io/sn0hu

我需要将值输入数组，然后在下一步中使用变量。值为result-＆gt; data-＆gt; tab-＆gt; unified_content-＆gt; item（如果header = title，则为type-＆gt; text，如果text = description）

脚本：

function getContent($data) {
    $tabs = $data->result->data->tab;
    foreach($tabs as $tab){
        $content = [];
        if(isset($tab->unified_content->item)) {
            foreach($tab->unified_content->item as $item) {
                if($item->type->name == 'header') {
                    $arr = [];
                    $arr['title'] = $item->text;
                } else {
                    $arr['description'] = $item->text;
                    $content[] = $arr;
                }                   
            }
            return $content;
        }   
    }
}

$test = getContent($data);
foreach ($test as $lol) {
    var_dump($lol);
}

现在输出：array（1）{[＆＃34; description＆＃34;] =＆gt; string（0）＆＃34;＆＃34; }

Answer 1

您需要在$content循环之前初始化foreach，然后将其返回。否则，您只返回unified_content->item存在的第一个标签中的内容。该选项卡只包含一个项目，没有标题和空文本。：

    "item": [{
        "id": 17229,
        "text": "",
        "align": "l",
        "type": {
            "id": 3,
            "name": "image"
        },
        "width": "l",
        "shape": "s",
        "swajp": 0,
        "icon": 273,
        "margin": 1,
        "image": [{
            "id": 10482,
            "src": "image.php?id=18432&app_id=5786&key=a1bd33754a582bc1094e5f1b170adbb4747b7bdb",
            "title": "V ned\u011bli 12.11. od 14:00 hrajeme v Bra\u0161kov\u011b",
            "width": 1920,
            "height": 1345
        }, {
            "id": 10480,
            "src": "image.php?id=18430&app_id=5786&key=62d75ca8ea4c16fdd6a4bec8c48848f692b843bf",
            "title": "Dom\u00e1c\u00ed prohra na penalty s Jedom\u011blicemi 2:3 (1:2) Pen: 2:4",
            "width": 1920,
            "height": 1218
        }, {
            "id": 10483,
            "src": "image.php?id=18433&app_id=5786&key=1e1479dcf8de55f57e29e1a16f428f4414c76032",
            "title": "Unho\u0161\u0165 spadla na 11. m\u00edsto v tabulce",
            "width": 1920,
            "height": 1280
        }, {
            "id": 49465,
            "src": "image.php?id=90502&app_id=5786&key=3103a185854b771cdad784950d343bb3e143bec6",
            "title": "\u00dasp\u011b\u0161n\u00fd fotbalov\u00fd kemp",
            "width": 1000,
            "height": 750
        }]
    }]

您还应该在内部循环之前初始化$arr，而不是if，以防没有header对象。

function getContent($data) {
    $tabs = $data->result->data->tab;
    $content = [];
    foreach($tabs as $tab){
        if(isset($tab->unified_content->item)) {
            $arr = [];
            foreach($tab->unified_content->item as $item) {
                if($item->type->name == 'header') {
                    $arr['title'] = $item->text;
                } else {
                    $arr['description'] = $item->text;
                    $content[] = $arr;
                }                   
            }
        }   
    }
    return $content;
}

Answer 2

下次请说清楚你在寻找什么（什么是＆＃34;好的输出＆＃34;？）。

使用json_decode（$ json_file，true）。即：

<?php

$json_file = file_get_contents("testing.json");
$json_decode = json_decode($json_file, true); //Sets it as an array

print_r($json_decode['result']['status']); //Will print out "done" in this case

?>

同样，这可能不是您正在寻找的答案，因为它并不清楚您在OP中寻找的是什么。

输出错误 - 数组（1）{[＆＃34; description＆＃34;] =＆gt; string（0）＆＃34;＆＃34; }

2 个答案: