我有以下功能可以转换数字列表：
sum()返回输出select lastname, firsname,
sum(case when upper(category) = 'W' then abs(principal) end) as Withdrawal,
sum(case when upper(category) = 'D' then abs(principal) end) as Deposit,
description
from table1 join
table2
on table2.id = table1.id join
table3
on table3.c = table2.c
where description = 'string'
group by lastname, firstname, description
如何让它返回输出import numpy as np
from math import *
def walsh_transform(x):
if len(x) > 3:
n = len(x)
m = trunc(log(n, 2))
x = x[0:2 ** m]
h2 = [[1, 1], [1, -1]]
for i in range(m - 1):
if i == 0:
h = np.kron(h2, h2)
else:
h = np.kron(h, h2)
return np.dot(h, x) / 2. ** m
arr = [1.0, 1.0, 1.0, 2.0, 0.0, 0.0, 0.0, 0.0]
print(walsh_transform(arr))
？即逗号分隔值？
答案 0 :(得分：2)
只需将最终结果投射到列表中，因为列表会以您想要的格式打印出来。
print(list(walsh_transform(arr)))
答案 1 :(得分：1)
您可以使用return [z for z in np.dot(h, x) / 2. ** m]代替return np.dot(h, x) / 2. ** m
答案 2 :(得分：1)
您可以将结果数组转换为list以获得所需的输出。
w = walsh_transform(arr) # w = [ 0.625 -0.125 -0.125 0.125 0.625 -0.125 -0.125 0.125]
print(list(w)) # output = [0.625, -0.125, -0.125, 0.125, 0.625, -0.125, -0.125, 0.125]
答案 3 :(得分：0)
尝试使用repr
print(repr(walsh_transform(arr))) # output = [0.625, -0.125, -0.125, 0.125, 0.625, -0.125, -0.125, 0.125]
或者，您可以将其投射到列表中：
print(list(walsh_transform(arr))) # output = [0.625, -0.125, -0.125, 0.125, 0.625, -0.125, -0.125, 0.125]
答案 4 :(得分：0)
您所要做的就是用逗号替换空白。
re.sub功能也应该起作用。