Question

我知道这个但是得到错误可以提供解决方案。

marker.setTitle('hii')

Answer 1

你没有创建表，它应该看起来像这样

DECLARE @TableName VARCHAR(500);

SET @TableName = N'businessmaster_'+CONVERT(VARCHAR(10),GetDate()-1,112);

EXEC (N'CREATE TABLE '+@TableName +' ( contentid int,Businessname varchar(50) )')

print @TableName
declare  @sql varchar(100)    

SET @sql = 'INSERT INTO '+ @TableName+' (contentid,Businessname) SELECT top 10 contentid,Businessname FROM businessmaster';
EXEC (@sql)

Answer 2

您没有创建表，如何向表中插入数据不存在：

DECLARE @TableName VARCHAR(MAX);
DECLARE @SQL NVARCHAR(MAX);
SET @TableName = N'businessmaster_'+
                 CONVERT(VARCHAR(10),GetDate()-1,112);

SET @SQL = N' CREATE TABLE '+@TableName + N' ( contentid int,Businessname varchar(50) )';

EXECUTE (@SQL);

SET @SQL = 'INSERT INTO '+ @TableName+' (contentid,Businessname) SELECT top 10 contentid,Businessname FROM businessmaster';

EXECUTE (@SQL);

<强> Demo

在动态表中插入数据

2 个答案: