用于GPS跟踪的SQL查询

Question

这是我的数据表 SQl Fiddle

它跟踪汽车表（我的事情列名是描述性的） 我每隔30秒就得到一辆车 现在我想要一份报告来获取Trip-Idle Detail

这是我的最后一次尝试

SELECT        carid, (SUM(CASE WHEN speed < 3 THEN 0 ELSE DATEDIFF(minute, b.trackold, b.TrackTime) END)) AS speeding, (SUM(CASE WHEN speed >= 3 THEN 0 ELSE DATEDIFF(minute, b.trackold, b.TrackTime) END)) 
 AS parked, round(sum(Distance / 1000), 2) AS Distance, TrackDay FROM            (SELECT        carid, TrackDay, TrackTime, trackold, speed, TrackDayOld, diff, Distance        FROM            (SELECT        carid, TrackTime, LAG(TrackTime, 1, NULL) OVER (PARTITION BY carid ORDER BY TrackTime) AS trackold, CONVERT(date, TrackTime) AS TrackDay, CONVERT(date, LAG(TrackTime, 1, NULL) OVER (PARTITION BY carid   ORDER BY TrackTime)) AS TrackDayOld, speed, datediff(minute, LAG(TrackTime, 1, NULL) OVER (PARTITION BY carid ORDER BY carid), TrackTime) AS diff, Distance FROM   T_Tracking) a WHERE        a.TrackDay = a.TrackDayOld) b GROUP BY carid, TrackDay

但这会让汽车每天都有记录

谢谢

Answer 1

这里我是如何解决我的问题的 我会将其标记为任何寻找相同情况的人的答案

SELECT        carid, (SUM(CASE WHEN speed < 3 THEN 0 ELSE DATEDIFF(minute, b.trackold, b.TrackTime) END)) AS speeding, (SUM(CASE WHEN speed >= 3 THEN 0 ELSE DATEDIFF(minute, b.trackold, b.TrackTime) END)) 
                     AS parked, round(sum(Distance / 1000), 2) AS Distance,TrackDay FROM    (SELECT        carid, TrackDay, TrackTime, trackold, speed, TrackDayOld, diff, Distance
                      FROM            (SELECT        carid, TrackTime, LAG(TrackTime, 1, NULL) OVER (PARTITION BY carid   ORDER BY TrackTime) AS trackold, CONVERT(date, TrackTime) AS TrackDay, CONVERT(date, LAG(TrackTime, 1, NULL) OVER (PARTITION BY carid  ORDER BY TrackTime)) AS TrackDayOld, speed, datediff(minute, LAG(TrackTime, 1, NULL) OVER (PARTITION BY carid ORDER BY carid), TrackTime) AS diff, Distance FROM  T_Tracking) a WHERE        a.TrackDay = a.TrackDayOld) b GROUP BY carid, TrackDay