我有一个视图,其中有detailview
和gridview
。在我的gridview
我有一个复选框。点击任何复选框,我都可以获得所选列的id
。以下是我的观点
//my DetailView
?= GridView::widget([
'dataProvider' => $dataProvider,
/*'filterModel' => $searchModel,*/
'columns' => [
['class' => 'yii\grid\CheckboxColumn', 'checkboxOptions' => function($d) {
return ['value' => $d['meter_id']];
}],
'Meter_Serial_Number',
'Issued_To',
'Store',
],
]); ?>
<a href="<?= URL::toRoute(['ogpheader/viewsetpdf', 'id'=>$model->id])?>" name="redirect" class="btn btn-primary" id="myid">Set PDF</a>
UI
注意:
detail view
来自模型,gridview
从query
生成,以查看然后选择数据。
现在我已经发出一个ajax
调用,将数据发送到控制器。
<?php
$url = Url::toRoute(['/ogpheader/viewsetpdf']);
$script = <<< JS
$(document).ready(function () {
$('#myid').click(function() {
var strValue = "";
$('input[name="selection[]"]:checked').each(function() {
if(strValue!="")
{
strValue = strValue + " , " + this.value;
}
else
strValue = this.value;
});
$.ajax({
url: '$url',
data: {
data: strValue,
},
type: 'post',
dataType: 'json',
success: function(data) {
alert(data);
},
});
})
});
JS;
$this->registerJs($script, static::POS_END);
?>
动作控制器
public function actionViewsetpdf($id)
{
$model = $this->findModel($id);
print_r($model);
$data = "";
if(isset($_POST['data']))
{
$data = json_decode($_POST['data']);
print_r($data);
}
else{
echo 'no data';
}
exit();
}
$id
是模型的ID,即detail view
的ID。我想通过我的detail view
和grid view
个所选项目来处理事情。
现在当我点击Set PDF
按钮时,我得到了以下结果
在输出图像中,我得到了我的模型的详细信息,即我的详细信息视图项,但对于我选择的网格视图项,我得到了no data
。我已经搜索过但无法找到帮助我的解决方案
更新1
更改了我的JS
和ajax
来电
$('#myid').on('click',function(e) {
e.preventDefault();
var strValue = "";
$('input[name="selection[]"]:checked').each(function() {
if(strValue!="")
{
strValue = strValue + " , " + this.value;
}
else
strValue = this.value;
});
// alert(strValue);
$.ajax({
url: '$url',
type: 'POST',
dataType: 'json',
data: 'data='+ strValue,
success: function(data) {
alert(data);
},
});
})
});
我得到的Xhr
中的输出是
common\models\Ogpheader Object( [_attributes:yii\db\BaseActiveRecord:private] => Array ( [id] => 54 [created_by] => 12 [created_at] => 2017-11-13 05:26:04 [updated_at] => [canceled_at] => [store_id] => 10 [status] => Prepared [issuer] => 88 [admin_incharge] => Faisal [project_manager] => Ali ) [_oldAttributes:yii\db\BaseActiveRecord:private] => Array ( [id] => 54 [created_by] => 12 [created_at] => 2017-11-13 05:26:04 [updated_at] => [canceled_at] => [store_id] => 10 [status] => Prepared [issuer] => 88 [admin_incharge] => Faisal [project_manager] => Ali ) [_related:yii\db\BaseActiveRecord:private] => Array ( ) [_errors:yii\base\Model:private] => [_validators:yii\base\Model:private] => [_scenario:yii\base\Model:private] => default [_events:yii\base\Component:private] => Array ( ) [_behaviors:yii\base\Component:private] => Array ( ))array(1) { ["data"]=> string(26) "99 , 100 , 101 , 102 , 103"}
但是当我删除e.preventDefault()
时,页面会被重定向到另一个视图,我得到的响应是
common\models\Ogpheader Object( [_attributes:yii\db\BaseActiveRecord:private] => Array ( [id] => 54 [created_by] => 12 [created_at] => 2017-11-13 05:26:04 [updated_at] => [canceled_at] => [store_id] => 10 [status] => Prepared [issuer] => 88 [admin_incharge] => Faisal [project_manager] => Ali ) [_oldAttributes:yii\db\BaseActiveRecord:private] => Array ( [id] => 54 [created_by] => 12 [created_at] => 2017-11-13 05:26:04 [updated_at] => [canceled_at] => [store_id] => 10 [status] => Prepared [issuer] => 88 [admin_incharge] => Faisal [project_manager] => Ali ) [_related:yii\db\BaseActiveRecord:private] => Array ( ) [_errors:yii\base\Model:private] => [_validators:yii\base\Model:private] => [_scenario:yii\base\Model:private] => default [_events:yii\base\Component:private] => Array ( ) [_behaviors:yii\base\Component:private] => Array ( )) no data
任何帮助都将受到高度赞赏。
答案 0 :(得分:1)
我认为$ url不适用于js代码, 例如,当你像这样点击#myid链接时,你可以通过jquery获取网址:
var url;
$('#myid').click(function() {
var strValue = "";
url = $(this).attr("href");
$('input[name="selection[]"]:checked').each(function() {
if(strValue!="")
{
strValue = strValue + " , " + this.value;
}
else
strValue = this.value;
$.ajax({
url: url,
data: {
data: strValue,
},
type: 'post',
dataType: 'json',
success: function(data) {
alert(data);
},
});
});
答案 1 :(得分:0)
你应该避免引用php var
$.ajax({
url: $url,
.....